I can only give possible combination of the ages. Had the sum of the ages been given, then the 3 specific numbers would have been derived.
We need to do prime factorization of 72.
72 ÷ 2 = 36
36 ÷ 2= 18
18 ÷ 2 = 9
9 ÷ 3 = 3
3 ÷ 1 = 1
1 x 2 x 2 x 2 x 3 x 3 = 72
Possible combinations:
1 x 8 x 9 = 72 1 + 8 + 9 = 18
1 x 4 x 18 = 72 1 + 4 + 18 = 23
2 x 4 x 9 = 72 2 + 4 + 9 = 15
3 x 4 x 6 = 72 3 + 4 + 6 = 13
Answer:
The multiples of 4 are: 4,8,12,16,20,24,28,32,36,40,44,.
Step-by-step explanation:
so no
Q = d - 12
q = 28 - d
d - 12 = 28 - d
d + d = 28 + 12
2d = 40
d = 40/2
d = 20 <== 20 dimes
q = d - 12
q = 20 - 12
q = 8 <== 8 quarters
Answer:
3
Step-by-step explanation:
C is sus btw
1x3=3
