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3 years ago

Which option is the correct interpretation of this numerical expression?

Mathematics

1 answer:

telo118 [61]3 years ago

7 0

Answer:

Step-by-step explanation:

bc 11×5=55 so you divide it and its 11-4=7 :)

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A coffee shop gives the customer a free cup of coffee after the purchase of 5 cups: a.) industrial marketing program b.) loyalty

AveGali [126]

I think it’s a loyalty marking program. I think it’s that because I feel like it’s the only answer that really makes sense bc the customer is being loyal to the service in order to receive their “reward”

3 0

2 years ago

Your start-up business is looking into the energy usage in the community of south lawndale. your sample size is 12 months. use t

Aleonysh [2.5K]

The confidence interval at 95% level is

7106.87 < μ< 14255.27

<h3>What is meant be mean and standard deviation?</h3>

The ratio of sum of observations to the total number of observation is known as mean. It is one of the central tendency in the statistics. It gives an idea about the central value present in the data. The most sensitive measure of central tendency is mean. It is very easy to calculate. Mean playa a crucial role in daily life. The two types of means are Arithmetic mean and Geometric mean.

Standard deviation is a measure in the statistics. The amount of variation of a set of values is known as standard deviation. Standard deviation is denoted by σ.

As per given data

90% confident level for amount of electricity used in community of Austin is

X-tx/2(n-1)s/√n < μ < X+ tx/2(n-1)s/√n

Here , n=12 , X=10681.07 , s=6893.87

Margin of error = tx/2(n-1)s/√n

=(1.796×6893.87)/√12

=3574.1996

=3574.19(approximately)

Therefore, 90% CI is,

10681.07-3574.19 ≤ μ<10681.07+3574.19

7106.87 < μ< 14255.27

To know more about mean and standard deviation, visit:

brainly.com/question/14720855

#SPJ4

5 0

1 year ago

What is the value of f ( − 3a ), if f ( x ) = 2x 2 + 4x ?

gogolik [260]

Answer:

d. 18a² - 12a

Step-by-step explanation:

f(x) = 2x² + 4x

f(-3a) = 2(-3a)² + 4(-3a)

2(-3a)² + 4(-3a)

2(9a²) + (-12a)

18a² - 12a

8 0

3 years ago

140.3 is 23% of what number?

LenaWriter [7]

600

explanation: well, since 140.3 divided by 600 is equal to 0.233833333... means that is that 140.3 is the 23 percent of 600

6 0

3 years ago

Read 2 more answers

Prove A-(BnC) = (A-B)U(A-C), explain with an example

NikAS [45]

Answer:

Prove set equality by showing that for any element $x$ , $x \in (A \backslash (B \cap C))$ if and only if $x \in ((A \backslash B) \cup (A \backslash C))$ .

Example:

$A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace$ .

$B = \lbrace0,\, 1 \rbrace$ .

$C = \lbrace0,\, 2 \rbrace$ .

$\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}$ .

$\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}$ .

Step-by-step explanation:

Proof for $[x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))]$ for any element $x$ :

Assume that $x \in (A \backslash (B \cap C))$ . Thus, $x \in A$ and $x \not \in (B \cap C)$ .

Since $x \not \in (B \cap C)$ , either $x \not \in B$ or $x \not \in C$ (or both.)

If $x \not \in B$ , then combined with $x \in A$ , $x \in (A \backslash B)$ .
Similarly, if $x \not \in C$ , then combined with $x \in A$ , $x \in (A \backslash C)$ .

Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ as required.

Proof for $[x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]$ :

Assume that $x \in ((A \backslash B) \cup (A \backslash C))$ . Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

If $x \in (A \backslash B)$ , then $x \in A$ and $x \not \in B$ . Notice that $(x \not \in B) \implies (x \not \in (B \cap C))$ since the contrapositive of that statement, $(x \in (B \cap C)) \implies (x \in B)$ , is true. Therefore, $x \not \in (B \cap C)$ and thus $x \in A \backslash (B \cap C)$ .
Otherwise, if $x \in A \backslash C$ , then $x \in A$ and $x \not \in C$ . Similarly, $x \not \in C \!$ implies $x \not \in (B \cap C)$ . Therefore, $x \in A \backslash (B \cap C)$ .

Either way, $x \in A \backslash (B \cap C)$ .

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ implies $x \in A \backslash (B \cap C)$ , as required.

8 0

2 years ago