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3 years ago

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The actual length of a in the triangle shown is 10 cm. Use the scale drawing of the triangle to find the actual length of side b

.
A) 0.18 cm
B) 12.5 cm
C) 16 cm
D) 48.5 cm

1 answer:

geniusboy [140]3 years ago

6 0

Umm Do you have A Picture For It Cause If You Don't Then I Can't Answer It

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zysi [14]

Your answer is Y=-4 5
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3 years ago

Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas

lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

$n(S) = n(s) + n(S \cap F)$

In which n(s) are those who are succeful but not freshmen and $n(S \cap F)$ are those who are succesful and freshmen.

By the same logic, we also have that:

$n(F) = n(f) + n(S \cap F)$

The union is:

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

In which

$n(S \cup F) = 58$

$n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)$

$n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)$

So

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

$58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)$

$n(S \cap F) = 24$

So the correct answer is:

b) 24

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Triangle ABC and DEF are right triangles, as shown. Triangle ABC is similar to triangle DEF. which ratios are equal to sin C?

Dafna11 [192]

Answer:

First option and Fourth option.

Step-by-step explanation:

To solve this exercise you need to use the following Trigonometric Identity:

$sin\alpha=\frac{opposite}{hypotenuse}$

In this case you know that:

$\alpha =C$

Since triangle ABC is similar to triangle DEF:

$\angle C=\angle F$

Let's begin with the triangle ABC.

You can identify that:

$opposite=AB\\hypotenuse=AC$

Then, substituing values, you get:

$sinC=\frac{AB}{AC}$

In triangle DEF, you know that:

$opposite=DE\\hypotenuse=DF$

So, substituing values, you get:

$sinF=sinC=\frac{DE}{DF}$

4 0

3 years ago

if the line AB with A(-1,5) and B(3,7) is perpendicular to the line CD WITH C(7,11) AND D(X,23). THEN X=?

MissTica

Answer:

x=1

Step-by-step explanation:

slope AB = (7-5) / (3 - -1) = 2 / 4 = 1/2

slope CD = (23-11) / (x-7) = 12 / (x-7)

12 / (x-7) = - 2 ... perpendicular to AB slope 1 = - 1/slope 2

-2 (x-7) = 12

-2x + 14 = 12

-2x = -2

x = 1

5 0

3 years ago