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juin [17]
2 years ago
11

Which of the following graphs shows a parabola with a vertex of (1,-9) and solutions of (-2,0) and (4,0)?

Mathematics
1 answer:
Mariulka [41]2 years ago
3 0

Answer:

Hello,

Step-by-step explanation:

Roots are -2 and 4

y=k*(x+2)(x-4)

Vertex = (1,-9) is a point of the parabola

-9=k*(1+2)(1-4) ==> k=1

Equation of the parabola is y=(x+2)(x-4)

But you don' t have given the graphs !!!!

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If the function f is given by f(x)=2x2−4, then which of the following represents the value of c such that f(c)=28?
Zigmanuir [339]
I believe the answer is C. 4
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Give me an example of quadratic equation.​
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X(x - 2) = 4 [upon multiplying and moving the 4 becomes x² - 2x - 4 = 0] x(2x + 3) = 12 [upon multiplying and moving the 12 becomes 2x² - 3x - 12 = 0] 3x(x + 8) = -2 [upon multiplying and moving the -2 becomes 3x² + 24x + 2 = 0]
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3 years ago
Solve for n in the literal equation a(n-2)+5=bn
Helga [31]

Answer:

<u><em>Answer is below</em></u>

Step-by-step explanation:

<em><u>a(n-2)+5=bn</u></em>

<em><u>Add -bn to both sides</u></em>

<em><u>an-2a+5+(-bn)=bn+(-bn)</u></em>

<em><u>an-bn-2a+5=0</u></em>

<em><u>add two a to both sides</u></em>

<em><u>an−bn−2a+5+(2a)=0+(2a)</u></em>

<em><u>an−bn+5=2a</u></em>

<em><u>Add -5 to both sides</u></em>

<em><u>an−bn+5+(-5)=2a+(-5)</u></em>

<em><u>an−bn=2a−5</u></em>

<em><u>Factor out our variable</u></em>

<em><u>n(a−b)=2a−5</u></em>

<em><u>Divide both sides by a-b</u></em>

<em><u>n(a-b)/a-b=2a-5/a-b</u></em>

<em><u>n=2a-5/a-b</u></em>

<em><u>Hope this helps</u></em>

7 0
3 years ago
Helpp me please!!!!!!
Alexeev081 [22]

Answer:

a. Inscribed angle = <WXY

b. Minor arc = arc(XY)

c. VWX

d. m(VWX) = 180°

e. m<VUW = 110°

Step-by-step explanation:

a. The angle, <WXY has its vertex on the circumference of the circle. Therefore, it can be referred to as an inscribed angle of the circle with center U.

Inscribed angle = <WXY

b. Arc(XY) is a minor arc because it is smaller than half of circle with center U.

Minor arc = arc(XY)

c. A semicircle is half of a full rotation for a circle. From the diagram, a semicircle is VWX

d. m(VWX) = Half the rotation of a full circle = 180°

e. m<VUW = arc(VW) (measure of central angle = measure of arc)

m<VUW = 110° (Substitution)

3 0
3 years ago
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