Here you're being asked to find the "perimeter" of the space, even tho' the problem doesn't specifically ask for it.
The formula for P is P = 2W + 2L.
Here the width, W, is 3 1/2 yds, and the length, L, is 4 2/3 yds. Subbing these two values into the formula for P (above) results in:
P = 2(3 1/2 yds) + 2(4 2/3 yds)
= 7 yds + 9 1/3 yds = 16 1/3 yds, total.
Answer
im only in year 9 do you expect me to know that ????????????????????????????
16 is the answer jxhsjcjaks
2+2-1 that's three quick maths.
The solution as in where do they intersect? if so, it would be 0.0769 and -0.0769
