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Anon25 [30]
2 years ago
13

A biology class has a total of 35 students. The number of females is 11 less than the number of males. How many males and how ma

ny females are in the class?
Mathematics
1 answer:
lord [1]2 years ago
3 0

Answer:

23 males and 12 females

Step-by-step explanation:

x = # of females

y = # of males

x + y = 35

x + x + 11 = 35

2x + 11 =35    (SUBTRACT 11 FROM BOTH SIDES)

2x = 24          (DIVIDE BOTH SIDES BY 2)

x = 12 females

x + y =35

12 + y = 35     (SUBTRACT 12 FROM BOTH SIDES)

y = 23 males

23 males + 12 females = 35 students

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What is x? I tried it but I don’t think I did it right.
sattari [20]

Answer:

x = 4

Step-by-step explanation:

When a tangent and a secant are drawn from an external point to a circle.

Then the product of the external part of the secant and the entire secant and the square of the measure of the tangent are equal, hence

x(x + 5) = 6²

x² + 5x = 36 ( subtract 36 from both sides )

x² + 5x - 36 = 0 ← in standard form

(x + 9)(x - 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 9 = 0 ⇒ x = - 9

x - 4 = 0 ⇒ x = 4

However, x > 0 ⇒ x = 4

8 0
3 years ago
What is the solution of x+8/5x-1>0?
DerKrebs [107]

Answer:

x<-8 or x>1/5

Step-by-step explanation:

\frac{x+8}{5x-1} >0

First we replace > symbol by = sign

\frac{x+8}{5x-1} =0

To solve for x we multiply 5x-1 on both sides

x+8 =0

x=-8

5x-1=0 solve for x

x= 1/5

WE got two values x=-8  and x= 1/5

Now we make a number line and check with each interval

x<-8,  -8<x<1/5,  x>1/5

Pick x= -9 and check with the given inequality

\frac{-9+8}{5(-9)-1} >0

1/46 >0 is true, so x<-8 satisfies our inequality

Pick x= 0 and check with the given inequality

\frac{0+8}{5(0)-1} >0

-8 >0 is false , -8<x<1/5 does not satifies our inequality

Pick x= 2 and check with the given inequality

\frac{2+8}{5(2)-1} >0

10/9>0 is true , x>1/5  satisfies our inequality

3 0
3 years ago
Read 2 more answers
8) What is the common ratio for this sequence?
Naddika [18.5K]

Step-by-step explanation:

it will 2.5 this is right answer option D

6 0
2 years ago
5(x+2)=20 explain step by step
garri49 [273]
Divide by 5 each side
X+2=4
Subtract 2 from each side
X=2

5(2+2)=20
Does work


In algebra when isolating (leaving alone on one side) x, you do the opposite operation, thus multiplying when you are trying to get rid of a division and vice versa
6 0
2 years ago
If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?
kondaur [170]

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here, x_1=-8, y_1=-6, x_2=-4, y_2=-14

$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)

$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)

$P(x, y) =(-6, -10)

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Here, x_1=-6, y_1=-10, x_2=-8, y_2=-6

r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}

r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}

r=\sqrt{(-2)^{2}+(4)^{2}}

r=\sqrt{20} units

The standard form of the equation of a circle is

(x-a)^{2}+(y-b)^{2}=r^{2}, where (a, b) are center and r is the radius.

Here, center = (–6, –10) and r=\sqrt{20}

(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}

(x+6)^{2}+(y+10)^{2}=20

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

4 0
2 years ago
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