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Answer:
A's mixture is more acidic.
Step-by-step explanation:
Given:
Two friends mix water and citric acid.
One (Let A) add 3 cups of citric acid for every 16 cups of water and another (Let B)adds 2 cups of citric acid for every 12 cups of water.
Now, we have to find that whose mixture is more acidic means:-
Solution:
A add 3 cups of citric acid for every 16 cups of water, the ratio =
B adds 2 cups of citric acid for every 12 cups of water =
Now, to find that who mix more citric acid in the mixture, firstly we will equalize the denominator of both fraction by taking LCM so that can be compare easily.
LCM of 16 and 12:- <u>48</u>
16 - 16, 32, <u>48</u>, 64, 80, 96....
12 - 12, 24, 36, <u>48, </u>60, 72.......
For friend A -
For friend B -
<em>We found that in terms of 48 cups of water, friend A mixes 9 cups of acid while friend B mixes 8 cups of acid, means A is adding more acid than B and</em> hence friend A's mixture is more acidic.
We are asked to solve for the angle AOB and we are given with the following values:
radius = 12 cm
length of AB = 15 cm
We can solve for angle AOC such as shown below:
sin AOC = opposite/hypotenuse
sin AOC = 7.5/12
∠AOC =38.68°
The angle subtended at the center of the circle is just twice of ∠AOC, then we have:
∠AOB = 38.68° x 2
∠AOB = 77.36°
The answer is 77° 21' 51.75".
radius = 12 cm
length of AB = 15 cm
We can solve for angle AOC such as shown below:
sin AOC = opposite/hypotenuse
sin AOC = 7.5/12
∠AOC =38.68°
The angle subtended at the center of the circle is just twice of ∠AOC, then we have:
∠AOB = 38.68° x 2
∠AOB = 77.36°
The answer is 77° 21' 51.75".