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miv72 [106K]
2 years ago
6

I really need help please!!!!!!!!

Mathematics
2 answers:
kolbaska11 [484]2 years ago
7 0
You already got the right answer there! That transformation is purely a reflection!
ki77a [65]2 years ago
6 0
Reflection across y axis …
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Please help I don't understand this and I was hoping someone could explain it to me please and thank you (:
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Answer:

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Step-by-step explanation:

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what is the leading term of the following polynomial? f(x)=5x4-3x3+9x2+6x-7 A.5x4. B.-3x4. C.9x2. D.6x​
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Answer:

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Step-by-step explanation:

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3 years ago
What are the roots of x in -10x2 + 12x − 9 = 0?
hoa [83]

Answer:

x_1=\frac{3(2+i\sqrt{6})}{10}

x_2=\frac{3(2-i\sqrt{6})}{10}

Step-by-step explanation:

Use the Quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac}}{2a}

You can identify that, in this case:

a=-10\\b=12\\c=-9

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x=\frac{-12\±\sqrt{12^2-4(-10)(-9)}}{2(-10)}

x=\frac{-12\±\sqrt{-216}}{-20}

Remember that:

i=\sqrt{-1}

Therefore,rewriting and simplifying, you get:

x=\frac{-12\±6i\sqrt{6}}{-20}

x=\frac{-6(2\±i\sqrt{6})}{-2(10)}

x=\frac{3(2\±i\sqrt{6})}{10}

Then, you get the following roots:

x_1=\frac{3(2+i\sqrt{6})}{10}

x_2=\frac{3(2-i\sqrt{6})}{10}

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