1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
katrin2010 [14]
3 years ago
9

Which of the following statements are not true in developing a confidence interval for the population mean?

Mathematics
1 answer:
frutty [35]3 years ago
8 0

Answer:

b) The width of the confidence interval becomes narrower when the sample mean increases.

Step-by-step explanation:

The confidence interval can be calculated as:

\bar{x} \pm \text{Test Statistic}\displaystyle\frac{\sigma}{\sqrt{n}}

a) The width of the confidence interval becomes wider as the confidence level increases.

The above statement is true as the confidence level increases the width increases as the absolute value of test statistic increases.

b) The width of the confidence interval becomes narrower when the sample mean increases.

The above statement is false. As the sample mean increases the width of the confidence interval increases.

c) The width of the confidence interval becomes narrower when the sample size n increases.

The above statement is true as the sample size increases the standard error decreases and the confidence interval become narrower.

You might be interested in
Factor the Trinomial
Andrews [41]

Answer:

(2x+1)(x+3)

Step-by-step explanation:

Not much explaining for that...

7 0
3 years ago
Read 2 more answers
What is the definition of ratio table
Wittaler [7]
A table with columns filled with pairs of numbers that have the same ratio.
4 0
3 years ago
Someone help me please. I don't just want the answer, I need an explanation on how it's done too.​
NARA [144]

Answer:

Below.

Step-by-step explanation:

f) (a + b)^3 - 4(a + b)^2  

The (a+ b)^2 can be taken out to give:

= (a + b)^2(a + b - 4)

= (a + b)(a + b)(a + b - 4).

g)  3x(x - y) - 6(-x + y)

=  3x( x - y) + 6(x - y)

= (3x + 6)(x - y)

= 3(x + 2)(x - y).

h) (6a - 5b)(c - d) + (3a + 4b)(d - c)

=  (6a - 5b)(c - d) + (-3a - 4b)(c - d)

= -(c - d)(6a - 5b)(3a + 4b).

i)  -3d(-9a - 2b) + 2c (9a + 2b)

= 3d(9a + 2b) + 2c (9a + 2b)

=  3d(9a + 2b) + 2c (9a + 2b).

= (3d + 2c)(9a + 2b).

j)  a^2b^3(2a + 1) - 6ab^2(-1 - 2a)

=  a^2b^3(2a + 1) + 6ab^2(2a + 1)

= (2a + 1)( a^2b^3 + 6ab^2)

The GCF of a^2b^3 and  6ab^2 is ab^2, so we have:

(2a + 1)ab^2(ab + 6)

= ab^2(ab + 6)(2a + 1).

4 0
3 years ago
Can someone rewrite the expression x^2 * x^-12 in the form of x^n. Pleasee
Ganezh [65]

Answer:

x^ -10 or 1/x^10

Step-by-step explanation:

5 0
3 years ago
Which number belongs to the solution set of the equation below? x - 7 = 35 A. 22 B. 28 C. 42 D. 41
TiliK225 [7]
Hey there!

To find a solution that would satisfy the value of x, the first thing you must do is to first solve for x. To solve x-7=35, you must add 7 to both sides to isolate x. This should result in x=42.

When you look at the answer choices given, notice that choice C is the solution for x, 42.

Therefore, your answer would be C. 42.

To check if this is correct, you can plug 42 back into the equation x-7=35 to see if you get a true statement:
42-7=35
35=35

Hope this helps!
6 0
3 years ago
Other questions:
  • Who can help me ! <br> .... thanks
    12·1 answer
  • Mario buys 2 pounds of hamburger and 1 pound of sausage. Sausage costs 10 cents more per pound than hamburger. If the total cost
    15·1 answer
  • Rewrite y = 9x + 7 into standard form.<br> Pleas help!
    7·2 answers
  • 140.132 round to the nearst hundreth
    5·2 answers
  • Find the value of x in the isosceles triangle shown below.​
    10·2 answers
  • Find the 4th term if the sequend in which a1 = 2 and a n+1 = -4a n + 2
    13·1 answer
  • Help please i will give brainliest
    10·1 answer
  • Plz answer ASAP tysm !
    8·1 answer
  • Find the slope from the table
    10·1 answer
  • 14 + -7 -3=????????????????????help
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!