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Dvinal [7]
3 years ago
11

G

Mathematics
1 answer:
Anon25 [30]3 years ago
8 0

Answer:

34.13 ounces

Step-by-step explanation:

Total amount of water drunk=3.5*9.75=34.13

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In ΔJKL, k = 9.6 cm, l = 2.7 cm and ∠J=43°. Find ∠L, to the nearest 10th of a degree.
Bogdan [553]

Answer:

L = 10.64°

Step-by-step explanation:

From the given information:

In triangle JKL;

line k = 9.6 cm

line l = 2.7 cm; &

angle J = 43°

we are to find angle L = ???

We can use the sine rule to determine angle L:

i.e

\dfrac{j}{SIn \ J} = \dfrac{l}{ SIn \ L}

Using Pythagoras rule to find j

i,e

j² = k² + l²

j² = 9.6²+ 2.7²

j² = 92.16 + 7.29

j² = 99.45

j = \sqrt{99.45}

j = 9.97

∴

\dfrac{9.97}{Sin \ 43} = \dfrac{2.7}{ Sin \ L}

{9.97 \times    Sin (L ) = (2.7 \times Sin \ 43)

=  Sin \ L = \dfrac{ (2.7 \times Sin \ 43)}{9.97 } \\ \\ =  Sin \ L = \dfrac{ (2.7 \times 0.6819)}{9.97 }  \\ \\  = Sin \ L = 0.18466 \\ \\  L = Sin^{-1} (0.18466) \\ \\  L = 10.64 ^0

3 0
3 years ago
Help~!
Murljashka [212]
A but im not as sure
8 0
3 years ago
This includes evaluate numerica expressions
kkurt [141]

Answer:

1. (29 + 19) ➗ 3

     (48) ➗ 3

     48➗ 3

There are 16 cards in each pile

Step-by-step explanation:

2. 14           3. 110           4. 71       5. 54          6. 16            7. 23

8. 75          9. 32           10. 22     11. 20         12. 48          13. 53

14. Spit 6 in half to get Melinda's length so the answer is 3

15.  No the answer is not the same because you have to minus 18 to 8 (which is in the parenthesis) so the answer is 10.  But the other way around you have to add 15 (which is in the parenthesis) plus 5.

I really hope I helped you

6 0
2 years ago
If the outliers are not included, what is the mean of the data set?
Aleksandr-060686 [28]
The mean of the data without the outliers will be B 65.
6 0
4 years ago
Please help me i dont know how to do the down part.
torisob [31]

Answer:

40, 60, 80, 100, 120, 140, 160, 180, 200

Step-by-step explanation:as the 12 goes up by 12 the 20 goes up by 20

8 0
3 years ago
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