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erik [133]
3 years ago
11

Best answer gets the brainliest! Find $a/b$ when $2\log{(a -2b)} = \log{a} + \log{b}$.

Mathematics
1 answer:
andrey2020 [161]3 years ago
5 0

By some properties of logarithms, rewrite the equation as

2\log(a-2b) = \log(a) + \log(b) \\\\ \log(a-2b)^2 = \log(ab)

so that

(<em>a</em> - 2<em>b</em>)² = <em>ab</em>

Expand the left side:

<em>a</em> ² - 4<em>ab</em> + 4<em>b</em> ² = <em>ab</em>

Rearrange terms to get a quadratic equation in <em>a</em>/<em>b</em> :

<em>a</em> ² - 5<em>ab</em> + 4<em>b</em> ² = 0

<em>b</em> must be greater than 0, otherwise log(<em>b</em>) doesn't exist, and the same goes for <em>a</em>. So we can divide by <em>b</em> ² to get

<em>a</em> ²/<em>b</em> ² - 5<em>a</em>/<em>b</em> + 4 = 0

Factorize and solve for <em>a</em>/<em>b</em> :

(<em>a</em>/<em>b</em> - 4) (<em>a</em>/<em>b</em> - 1) = 0

==>   <em>a</em>/<em>b</em> = 4   or   <em>a</em>/<em>b</em> = 1

However, if <em>a</em>/<em>b</em> = 1, then <em>a</em> = <em>b</em> makes <em>a</em> - 2<em>b</em> = -<em>b</em>. But we must have <em>b</em> > 0, so we omit the second solution and end up with

<em>a</em>/<em>b</em> = 4

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3 0
3 years ago
Q1. Find the measure of angle 1. Show your work.
OlgaM077 [116]

Answer:

1. 110°

2. 139°

Step-by-step explanation:

1. 180° in a triangle

180 - 40 - 30 = 110°

2. 180° in a triangle

angles on a straight line add up to 180°

180 - 64 - 75 = 41°

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4 0
3 years ago
The Bayside Bugle charges by the word to run automotive ads. The newspaper
11111nata11111 [884]

Answer:

$20.45

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Since the Bayside Bugle charges $18 for the first 20 words and there is more than 20 words in the ad you take 27-20 and you get 7 additional words.

Now we know that we already have to pay $18 for the first $20 words.

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Next we add up our two numbers (2.45+18) we get the total of $20.45 fro a 27-word ad.

I hope this helps :)

8 0
3 years ago
Which expression shows 36 + 63 as the product of their greatest common factor and the sum of two whole numbers with no common fa
jarptica [38.1K]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~~

The first thing we know is that all the answers equal 99, so we cannot cross any answer off, however, what we want to know is what answer (after distribution) looks like 36 + 63...

A.) 11(3 + 6) > 33 + 66

Does 33+66 look like 36+63?

NO

B.) 9(4 + 7) > 36 + 63

Does 36+63 look like 36+63?

YES

C.) 11(4 + 5) > 44 + 55

Does 44+55 look like 36+63?

NO

D.) 3(15 + 18) > 45 + 54

Does 45+54 look like 36+63?

NO

So...

The answer is: B.) 9(4 + 7)


4 0
3 years ago
What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)
lbvjy [14]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

8 0
2 years ago
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