Question:
The cost of 12 kg sugar is $240 what will be the cost of 3 kg sugar.
Given:
- Cost of 12 kg sugar = $240
To find?
Answer :
<u>To find </u><u>c</u><u>o</u><u>s</u><u>t</u><u> </u><u>of</u><u> </u><u>3kg sugar first we have to find cost of 1 kg sugar</u><u>.</u>
- Cost of 1 kg sugar = Cost of total no. of sugar ÷Total sugar
- Cost of 1 kg sugar = $240/12
- Cost of 1 kg sugar = $20
<u>Now Let's find cost of 3 kg sugar</u>
Cost of 3kg sugar = total no of sugar ×Cost of 1 kg sugar
Cost of 3kg sugar = 3×$20
Cost of 3kg sugar = $60
A is x times larger than B
4*10^-3=x times larger than 4*10^-4
4*10^-3=x*4*10^-4
divide both sides by 4
10^-3=x*10^-4
divide both sides by 10^-4
10^1=x
10^1=10
answer is 10 times or C
Answer:
Step-by-step explanation:
both angles must add up to 180 so
6x+12+3x+63 must =180
= 9x+75
9x+75=180
-75 -75
9x=105
x=11.66
meaning A is approximately 81.96
Answer:
x=15 in.
Step-by-step explanation:
If the parallelograms are equal (I assume they are), then the ratios are the same. 12 is 3/4 of 16. 3/4 of 20 is 15.
