Answer:
Mason has
- 16 20¢ stamps;
- 25 3¢ stamps;
- 40 49¢ stamps.
Step-by-step explanation:
Let x be the number of 20¢ stamps, then the number of 3¢ stamps is x + 9.
Mason has 56 total 49¢ and 20¢ stamps, then the number of 49¢ stamps is 56 - x.
Amounts:
- in 49¢:
cents; - in 20¢:
cents; - in 3¢:
cents.
Total amount:

- $23.55.
Hence,

Mason has
- 16 20¢ stamps;
- 25 3¢ stamps;
- 40 49¢ stamps.
Answer:
Step-by-step explanation:
1 <em>4(1) + 2 6</em>
3 <em>4(3) + 2 14</em>
6 <em>4(6) + 2 26</em>
0 <em>0 + 3 3</em>
2 <em>2 + 3 5</em>
4 <em>4 + 3 7</em>
<em>1 1 - 1 </em> 0
<em>3 3 - 1</em> 2
<em>5 5 - 1</em> 4
17+x=57.
So, subtract 17 from both sides
X=40
Answer:
The answer is c or x=25
Step-by-step explanation: