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irakobra [83]
3 years ago
9

What is AE? Enter your answer in the box?

Mathematics
1 answer:
Nataly [62]3 years ago
5 0

Answer:

AE = 18 units

Step-by-step explanation:

Δ AEB and Δ DEC are similar , then corresponding sides are in proportion, that is

\frac{AE}{DE} = \frac{AB}{DC} , substitute values

\frac{2x+4}{x+8} = \frac{12}{10} ( cross- multiply )

10(2x + 4) = 12(x + 8) ← distribute parenthesis on both sides

20x + 40 = 12x + 96 ( subtract 12x from both sides )

8x + 40 = 96 ( subtract 40 from both sides )

8x = 56 ( divide both sides by 8 )

x = 7

Then

AE = 2x + 4 = 2(7) + 4 = 14 + 4 = 18 units

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On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre
Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

P(x)=\frac{e^{-at}*(at)^{x} }{x!}

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}

P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

P(x)=\frac{e^{-at}*(at)^{x} }{x!}

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}

P(0)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{0}}{0!}=0.2231

Finally, P(x≥1) is:

P(x≥1) = 1 - 0.2231 = 0.7769

3 0
3 years ago
Andy bought 4.85 meters of cord. The cord cost 98¢ per meter. He also purchased 9.6 meters of copper wire. It cost $1.29 per met
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3 0
3 years ago
Use the euclidean algorithm to find
kvasek [131]
A)
18=1\cdot12+6
12=2\cdot6+0
\implies\mathrm{gcd}(12,18)=6

b)
201=1\cdot111+90
111=1\cdot90+21
90=4\cdot21+6
21=3\cdot6+3
6=2\cdot3+0
\implies\mathrm{gcd}(111,201)=3

c)
1331=1\cdot1001+330
1001=3\cdot330+11
330=30\cdot11+0
\implies\mathrm{gcd}(1001,1331)=11

d)
54321=4\cdot12345+4941
12345=2\cdot4941+2463
4941=2\cdot2463+15
2463=164\cdot15+3
15=5\cdot3+0
\implies\mathrm{gcd}(12345,54321)=3

e)
5040=5\cdot1000+40
1000=25\cdot40+0
\implies\mathrm{gcd}(1000,5040)=40

f)
9888=1\cdot6060+3828
6060=1\cdot3828+2232
3828=1\cdot2232+1596
2232=1\cdot1596+636
1596=2\cdot636+324
636=1\cdot324+312
324=1\cdot312+12
312=26\cdot12+0
\implies\mathrm{gcd}(9888,6060)=12
8 0
3 years ago
Can someone please help me with math.
romanna [79]
Answer:

I think it’s A
6 0
3 years ago
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