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nata0808 [166]
2 years ago
11

The number of adults who attend a county fair (measured in hundreds of people) is represented by the function a(d)=−0.3d2+4d+9 ,

where d is the number of days since the fair opened. The number of children who attend the same county fair (measured in hundreds of people) is represented by the function c(d)=−0.2d2+5d+11 , where d is the number of days since the fair opened. What function, f(d) , can be used to determine how many more children than adults attend the fair on any day?
Mathematics
2 answers:
denis-greek [22]2 years ago
7 0
<span> f(d)=0.1d2+d+2 would be your answer I believe</span>
Lesechka [4]2 years ago
6 0

Given is the function for number of adults who visit fair at day 'd' after its opening, a(d) = −0.3d² + 4d + 9.

Given is the function for number of children who visit fair at day 'd' after its opening, c(d) = −0.2d² + 5d + 11.  

Any function f(d) to find excess of children more than adults can be written as follows :-  

f(d) = c(d) - a(d).

⇒ f(d) = (−0.2d² + 5d + 11) - (−0.3d² + 4d + 9)

⇒ f(d) = -0.2d² + 0.3d² + 5d - 4d + 11 - 9

⇒ f(d) = 0.1d² + d + 2

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3 years ago
The vector ab has a magnitude of 20 units and is parallel to the<br> vector 4i + 3j.<br> find ab.
stepladder [879]

The vector ab has a magnitude of 20 units and is parallel to the

vector 4i + 3j. Hence, The vector AB is 16i + 12j.

<h3>How to find the vector?</h3>

If we have given a vector v of initial point A and terminal point B

v = ai + bj

then the components form as;

AB = xi + yj

Here, xi and yj are the components of the vector.

Given;

The vector ab has a magnitude of 20 units and is parallel to the

vector 4i + 3j.

magnitude

\sqrt{4^2 + 3^2} \\\\\sqrt{16 + 9} \\\\= 5

Unit vector in direction of resultant = (4i + 3j) / 5

Vector of magnitude 20 unit in direction of the resultant

= 20  x (4i + 3j) / 5

= 4 x (4i + 3j)

= 16i + 12j

Hence, The vector AB is 16i + 12j.

Learn more about vectors;

brainly.com/question/12500691

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7 0
1 year ago
I need help with this question.
Alborosie

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Step-by-step explanation:

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5 0
2 years ago
Find the x and y intercept for f(x)=x^2-3x-40
Dahasolnce [82]

To find the y-intercept, simply set the value of x equal to 0, and solve for y, or f(x).

f(x) = 0^2 - 3(0) - 40

f(x) = -40

<h3>The y-intercept is -40.</h3>

Because this is a 2nd degree polynomial, we cannot find the x-intercepts in one step, and must instead use one of a few different methods.

In this case, we're going to use the quadratic formula:

\frac{-b +/- \sqrt{b^2 - 4ac} }{2a}

Plug in the values.

3 +/- √(-3^2 + 160) / 2

3 +/- √169 / 2

3 +/- 13 / 2

(3 + 13) / 2 = 16 / 2 = 8

(3 - 13) = -10 / 2 = -5

<h3>The x intercepts are 8, and -5.</h3>
3 0
3 years ago
Please help!!! Only need help with number 4
Harman [31]
With the symbols given us the symbol for ten and use the symbol for zero 3 times
5 0
3 years ago
Read 2 more answers
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