Answer:
1 is 45. 14 is 90
Step-by-step explanation:
Answer:
A) 53
B) 53%
C) 37%
D) 63%
E) Yes.
Step-by-step explanation:
A) 53 people did not get headaches at all.
B) To solve for the percentage of participants that reported they did not get a migraine headache, you will need to divide out of the TOTAL number of people:
53/100= .53 --> Convert to percentage--> .53×100 = 53%.
C) To find this value, you will need to divide out of the amount of people that took MEDICINE and got a headache:
22/60≈0.367--> Convert to percentage --> 0.367×100≈37%
D) This percentage will be found out of who did NOT take the medicine:
25/40= 0.625 --> Convert to percentage --> 0.625×100≈63%
E) The medicine did help prevent migraine headaches because the percentage that got <u>migraines with the medicine is lower</u> than the percentage that got <u>migraines WITHOUT the medicine.</u>
Answer:

Step-by-step explanation:
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The "<em>constant rate of change</em>" is also known as the slope (in straight line equations).
The equation is in <em>slope-intercept form</em>.
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<em>Slope-Intercept Form is: </em>
<em></em>
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<em>Since '5' takes up 'm's spot, it is the slope, or the constant rate of change. </em>
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<em>Hope this helps.</em>
Correct Ans:Option A. 0.0100
Solution:We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.
First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:

So, 90 converted to z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.
Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.