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Finger [1]
3 years ago
5

Please, PLEASE help me! It’s due today! Please answer it properly! I’ll give Brainliest if the answer is correct, thank you In a

dvance!
1. What elements belongs to Set A and Set B?

2. Is there a repetition of the first elements in the ordered pairs? How about in second elements of the ordered pairs?

3. Does the set of ordered pairs represent a relation?

4. How is a relation represented?

This is in grade 8. but somehow, brainly put me in high school cus I’m 15yrs hh

Mathematics
1 answer:
coldgirl [10]3 years ago
3 0

Answer:

I wish I could help but I forgot how to do this, sorry. :(

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2.Mauricio tanqueó su auto en una estación de gasolina. Si el galón costo $ 7.000 y él pagó 12.250 por el servicio, ¿Qué fracció
Anettt [7]

Answer:

4/7

Step-by-step explanation:

2.Mauricio llenó su auto en una gasolinera. Si el galón le costó $ 7,000 y él pagó 12,250 por el servicio, ¿qué fracción es la cantidad de galones que pagó Mauricio?

La fracción por la cantidad de galones que pagó Mauricio se calcula como:

Cantidad de galones / Cantidad total pagada por el servicio

= $ 7000 / $ 12,250

= 4/7

Por lo tanto, la fracción que es la cantidad de galones que pagó Mauricio es 4/7

8 0
3 years ago
Pls I need help with this ASAP pls The first question. Thanks alot
olya-2409 [2.1K]

Answer:

Q = 28

Step-by-step explanation:

3 0
3 years ago
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Solve for x and show work
alukav5142 [94]

answer

long press i

Step-by-step explanation:

it's impossible to find out

5 0
2 years ago
Find the locus of a point such that the sum of its distance from the point ( 0 , 2 ) and ( 0 , -2 ) is 6.
jok3333 [9.3K]

Answer:

\displaystyle \frac{x^2}{5}+\frac{y^2}{9}=1

Step-by-step explanation:

We want to find the locus of a point such that the sum of the distance from any point P on the locus to (0, 2) and (0, -2) is 6.

First, we will need the distance formula, given by:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let the point on the locus be P(x, y).

So, the distance from P to (0, 2) will be:

\begin{aligned} d_1&=\sqrt{(x-0)^2+(y-2)^2}\\\\ &=\sqrt{x^2+(y-2)^2}\end{aligned}

And, the distance from P to (0, -2) will be:

\displaystyle \begin{aligned} d_2&=\sqrt{(x-0)^2+(y-(-2))^2}\\\\ &=\sqrt{x^2+(y+2)^2}\end{aligned}

So sum of the two distances must be 6. Therefore:

d_1+d_2=6

Now, by substitution:

(\sqrt{x^2+(y-2)^2})+(\sqrt{x^2+(y+2)^2})=6

Simplify. We can subtract the second term from the left:

\sqrt{x^2+(y-2)^2}=6-\sqrt{x^2+(y+2)^2}

Square both sides:

(x^2+(y-2)^2)=36-12\sqrt{x^2+(y+2)^2}+(x^2+(y+2)^2)

We can cancel the x² terms and continue squaring:

y^2-4y+4=36-12\sqrt{x^2+(y+2)^2}+y^2+4y+4

We can cancel the y² and 4 from both sides. We can also subtract 4y from both sides. This leaves us with:

-8y=36-12\sqrt{x^2+(y+2)^2}

We can divide both sides by -4:

2y=-9+3\sqrt{x^2+(y+2)^2}

Adding 9 to both sides yields:

2y+9=3\sqrt{x^2+(y+2)^2}

And, we will square both sides one final time.

4y^2+36y+81=9(x^2+(y^2+4y+4))

Distribute:

4y^2+36y+81=9x^2+9y^2+36y+36

The 36y will cancel. So:

4y^2+81=9x^2+9y^2+36

Subtracting 4y² and 36 from both sides yields:

9x^2+5y^2=45

And dividing both sides by 45 produces:

\displaystyle \frac{x^2}{5}+\frac{y^2}{9}=1

Therefore, the equation for the locus of a point such that the sum of its distance to (0, 2) and (0, -2) is 6 is given by a vertical ellipse with a major axis length of 3 and a minor axis length of √5, centered on the origin.

5 0
3 years ago
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Sophie [7]

Step-by-step explanation:

340 046 9411Collect the contact numbers of the potential customers (could be friends or relatives initially). Create a whats app broadcast list and send them the new products or offers with image to them regularly.

One more thing that helps is advertisement banners on public places such as bus depot, railway stations, etc…

Last but not the list. A COOL customer experience to the customers even though they do not buy anything.

Hope these helps. There are many other important factors as well. You can ask any time for any help in this. Would be glad to help. :)

8 0
2 years ago
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