Answer:
0.275
Step-by-step explanation:
We want to write 11 out of 40 batters as a decimal.
We can write 11 out of 40 as a fraction to get:
![\frac{11}{40}](https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B40%7D%20)
Note that:
![\frac{11}{40} = \frac{1}{4} \times \frac{11}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B40%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B4%7D%20%20%5Ctimes%20%20%5Cfrac%7B11%7D%7B10%7D%20)
This implies that:
![\frac{11}{40} = 0.25 \times 1.1](https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B40%7D%20%20%3D%200.25%20%20%5Ctimes%201.1)
This gives us
![\frac{11}{40 } = 0.275](https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B40%20%7D%20%20%3D%200.275)
Let x gallons be the amount of pure antifreeze that should be added to the 30% solution to produce a solution that is 65% antifreeze. Then the total amount of antifreeze solution will be x+3 gallons.
There are 30% of pure antifreeze in 3 gallons of solution, then
3 gallons - 100%,
a gallons - 30%,
where a gallons is the amount of pure antifreeze in given solution.
Mathematically,
![\dfrac{3}{a}=\dfrac{100}{30},\\ \\a=\dfrac{3\cdot 30}{100}=0.9\ gallons.](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7Ba%7D%3D%5Cdfrac%7B100%7D%7B30%7D%2C%5C%5C%20%5C%5Ca%3D%5Cdfrac%7B3%5Ccdot%2030%7D%7B100%7D%3D0.9%5C%20gallons.)
Now in new solution there will be x+0.9 gallons of pure antefreeze.
x+3 gallons - 100%,
x+0.9 - 65%
or
![\dfrac{x+3}{x+0.9}=\dfrac{100}{65},\\ \\65(x+3)=100(x+0.9),\\ \\65x+195=100x+90,\\ \\35x=105,\\ \\x=3\ gallons.](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%2B3%7D%7Bx%2B0.9%7D%3D%5Cdfrac%7B100%7D%7B65%7D%2C%5C%5C%20%5C%5C65%28x%2B3%29%3D100%28x%2B0.9%29%2C%5C%5C%20%5C%5C65x%2B195%3D100x%2B90%2C%5C%5C%20%5C%5C35x%3D105%2C%5C%5C%20%5C%5Cx%3D3%5C%20gallons.)
Answer: he should add 3 gallons of pure antifreeze.
Answer:
please mark me brainlist
Step-by-step explanation:
Correct answer is 0.2
0.2 * 0.2 is 0.04
then 0.04 * 0.2 = 0.008