Using the z-distribution, the 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 99% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 2.575.
The estimate and the sample size are given by:
.
Then the bounds of the interval are:
The 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer:
26
Step-by-step explanation:
SORRY IF IM WRONG
Answer: The answer is D
Step-by-step explanation: Hope this helps
I think inside the triangle......
Answer:
171
Step-by-step explanation:
180 - (5% × 180)
180 - 5% × 180
(1 - 5%) × 180
(100% - 5%) × 180
95% × 180
95 ÷ 100 × 180
95 × 180 ÷ 100
17,100 ÷ 100 = 171.