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Nataly_w [17]
2 years ago
8

Simplify 2- 5/8 and -2 3/5 A. -6 33/40 B. 4- 3/8 C. 4 3/8 d. 6 33/40

Mathematics
1 answer:
worty [1.4K]2 years ago
4 0

Answer:

Step-by-step explanation:

Convert mixed fraction to improper fraction.

-2\dfrac{5}{8}*(-2\dfrac{3}{5})=\dfrac{-21}{8}*\dfrac{-13}{5}\\

                    =\dfrac{(-21)*(-13)}{8*5}\\\\\\=\dfrac{273}{40}\\\\=6\dfrac{33}{40}

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Answer:

(1-\sqrt{2})a^2

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a

Thus,

MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a

Consider isosceles triangle MSC. In this triangle

MS=MC=(\sqrt{2}-1)a.

The area of this triangle is

A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}

Consider right triangle PTS. The area of this triangle is

A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2

5 0
3 years ago
The following exchange rate is given: £1=1.35 Dollars. Convert £9 into dollars
alexandr1967 [171]

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Step-by-step explanation:

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3 years ago
Write ✓-3 in simplest radical form.
olga nikolaevna [1]

Step-by-step explanation:

In simplest radical form

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Which expression is equivalent to -6(3x-2/3)
Fiesta28 [93]

Answer:

Solution given:

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distribute it

-18x+6*⅔

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3 0
2 years ago
Points J, K and L are collinear with J between L and K. If KJ = 2x-3, LJ= 4x-8, solve for x:
notsponge [240]

Your question is incomplete, here is the complete form.

Points J, K and L are collinear with J between L and K.  If KJ = 2x - 3, LK = 9x + 7 and LJ = 4x - 8,  solve for x:

Answer:

The value of x is -6 ⇒ B

Step-by-step explanation:

∵ J, K, and L are collinear

→ That means they form a straight segment

∵ J is between K and L

→ That means J divides LK into two segments KJ and LJ

∴ LK = KJ + LJ

∵ LK = 9x + 7

∵ KJ = 2x - 3

∵ LJ = 4x - 8

→ Substitute them in the equation above

∴ 9x + 7 = (2x - 3) + (4x - 8)

→ Add the like terms in the right side

∵ 9x + 7 = (2x + 4x) + (-3 - 8)

∴ 9x + 7 = 6x + -11

∴ 9x + 7 = 6x - 11

→ Subtract 7 from both sides

∵ 9x + 7 - 7 = 6x - 11 - 7

∴ 9x = 6x - 18

→ Subtract 6x from both sides

∵ 9x - 6x = 6x - 6x - 18

∴ 3x = -18

→ Divide both sides by 3

∵ \frac{3x}{3}=\frac{-18}{3}

∴ x = -6

∴ The value of x is -6

8 0
2 years ago
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