The other quantity which might be of interest is initial velocity
<h3>What is maximum height?</h3>
The maximum height of the object can be defined as the highest vertical position along its trajectory line.
The range of the projectile is also known as the horizontal displacement of the projectile. It is largely dependent on the initial velocity of the object.
If;
- v is the initial velocity
- g = acceleration due to gravity
- H = maximum height in meters
- θ = angle of the initial velocity from the horizontal plane (radians or degrees).
Maximum height of projectile is given by the formula:
From this, we can deduce that another quantity of interest is initial velocity
Thus, the other quantity which might be of interest is initial velocity
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Answer:
9.48 mm
Step-by-step explanation:
C=59.59 mm
59.59=2*3.14*r
r=9.48 mm
The first thing we are going to do for this case is define variables.
We have then:
y = the cost of the box
x = one side of the square base
z = height of the box
The volume of the building is 14,000 cubic feet:
x ^ 2 * z = 14000
We cleared z:
z = (14000 / x ^ 2)
On the other hand, the cost will be:
floor = 4 (x ^ 2)
roof = 3 (x ^ 2)
for the walls:
1 side = 16 (x * (14000 / x ^ 2)) = 16 (14000 / x)
4 sides = 64 (14000 / x) = 896000 / x
The total cost is:
y = floor + roof + walls
y = 4 (x ^ 2) + 3 (x ^ 2) + 896000 / x
y = 7 (x ^ 2) + 896000 / x
We derive the function:
y '= 14x - 896000 / x ^ 2
We match zero:
0 = 14x - 896000 / x ^ 2
We clear x:
14x = 896000 / x ^ 2
x ^ 3 = 896000/14
x = (896000/14) ^ (1/3)
x = 40
min cost (y) occurs when x = 40 ft
Then,
y = 7 * (40 ^ 2) + 896000/40
y = 33600 $
Then the height
z = 14000/40 ^ 2 = 8.75 ft
The price is:
floor = 4 * (40 ^ 2) = 6400
roof = 3 * (40 ^ 2) = 4800
walls = 16 * 4 * (40 * 8.75) = 22400
Total cost = $ 33600 (as calculated previously)
Answer:
The dimensions for minimum cost are:
40 * 40 * 8.75
Fist lets find the % of people using boats
100%- (36+53+2)= 9%
then find the number of people of 9%
200= 100%
B=9%
100B=200x9
B= 18
S=cost per student ticket
a=cost per adult ticket
value=(students vlue)+(adults value)
student value=(cost per student) times number of students
adult value=(cost per adult) times number of adults
you sell 8 adult and 6 students and that is a value of 126
8a+6s=126
friend sell12 adult and 13 student and get 209
12a+13s=209
so we have
8a+6s=126 and
12a+13s=209
it might help to simplify the first equaiton by dividing by 2
4a+3s=63
we have
4a+3s=63
12a+13s=209
multiply first equaton by -3
-12a-9s=-189
add to secont equaiton
12a+13s=209
<u>-12a-9s=-189 +
</u>0a+4s=20<u> </u>
4s=20
divide 4
s=5
each student ticket costs $5.00
