The number of companies is quite large. That is, n is quite large.
The probability that a company declares bankruptcy is quite small , p is quite small.
np = the mean number of bankruptcies = 2 = a finite number.
Hence we can apply Poisson distribution for the data.
P (x=5 | mean =2) = e-2 25/5! = e-2 * 32/120 = 0.036089
Alternatively
=poisson(5,2,0) = 0.036089
P(x≥ 5 | mean =2) = 1- P( x ≤ 4) = 1- e-2 (1+2+22/2!+23/3!+24/4!)= 1-e-2 (1+2+2+8/6+16/24)= 1-e-2(7)
=0.052653
Alternatively
= 1- poisson(4,2,1) =0.052653
P(X > 5 | mean =2) = 1- p(x
≤ 5) =1- e-2 (1+2+22/2!+23/3!+24/4!+25/5!)= 1-e-2(7+4/15)
=0.016564
alternatively=1-poisson(5,2,1)
=0.016564
It is important to go through details that are provided in the question. Based on those details the answer to the question can be easily deduced.
Let us assume the number of lions at the zoo = x
Number of male lions in the zoo = 2
Then
(1/6) * x = 2
x/6 = 2
x = 2 * 6
= 12
So there are a total of 12 lions in the zoo. I hope the procedure is clear enough for you to understand. Using this method, it will be possible for you to do similar problems in future without requiring any help from outside. Only be careful about the calculation part.
Gg easy
point slope:
for opint (x1,y1) and slope m
y-y1=m(x-x1)
so example
(1,2) and slope 3
y-2=3(x-1)
slope intercept
y=mx+b
m=slope
b=y intercept
if slope is 2 and y intercept is 3
y=2x+3
standard form
Ax+By=C
easies of all, just put randome numbers
2x+3y=4
A=2
B=3
C=4
