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Galina-37 [17]
2 years ago
11

Please answer, I need help

Mathematics
2 answers:
Mashcka [7]2 years ago
4 0

Answer:

answer is 9

Step-by-step explanation:

p - ( q - (m +q) )

make m = 4

p = 5

q = 3

5 - ( 3 - ( 4+3) )

5 - ( 3 - 7 )

5 - - 4

= 9

Ymorist [56]2 years ago
4 0

Answer:

3

Step-by-step explanation:

This might look a bit confusing but its really simple when you break it down...

So what they're asking is to evaluate the problem (in other words, solve the problem.)

Step 1: Substitute the variables m = 4, p =5 and q = 3

P - (9 - (m+q)) OR

5 - (9 - ( 4 + 3)

Step 2 : Order of operation, solve in parenthesis first.

5 - (9 - ( 4 + 3))

        ( 9  -  7)

     5   -   ( 2 )

Step 3 : Solve

5 - 2 = 3

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Find an equation of the line that passes through the points (-5, -3) and (3, 1)
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\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{-3})\quad (\stackrel{x_2}{3}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{(-3)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-5)}}}\implies \cfrac{1+3}{3+5}\implies \cfrac{4}{8}\implies \cfrac{1}{2}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{\cfrac{1}{2}}[x-\stackrel{x_1}{(-5)}]\implies y+3=\cfrac{1}{2}(x+5) \\\\\\ y+3=\cfrac{1}{2}x+\cfrac{5}{2}\implies y=\cfrac{1}{2}x+\cfrac{5}{2}-3\implies y = \cfrac{1}{2}x-\cfrac{1}{2}

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Vladimir79 [104]
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