Answer:
(1.8, -2.6) and (-1, 3)
Step-by-step explanation:


From the first equation

Applying to the second equation

Solving the equation we get

At x = 1.8
Applying in first equation

At x = -1
Applying in first equation

∴ The circle and line intersect at points (1.8, -2.6) and (-1, 3)
Honestly it's fun and people need to stop hating on it just because most of the people are toxic and weird. I don't play it, but It's really not worth the hate. People just hate just to hate about it.
Same with ro blox.
Answer:
B. f(x)
D. h(x)
Step-by-step explanation:
An exponential function will have a common ratio.
We check and see if the consecutive terms has a common ratio.
For f(x),

This is not an exponential sequence.
For g(x), we have:

For h(x),

This is not an exponential sequence
For k(x),

A) The population and sample mean are always the same ... in this case, it is 20.6 minutes.
<span>b) First convert the data to z-values: </span>
<span>P(X<18) = P(z < (18-20.6)/8.4) = P(z< -0.3095) </span>
<span>Now, using a Standard Normal table, look up z= -0.3095 </span>
<span>P(X<18) = 0.3785 </span>
<span>Hope that helps</span>