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nignag [31]
3 years ago
11

Solve the system of linear equations and check any solution algebraically

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
6 0
It is pretty long, hope you understand 
  x+y+z=6
+
  2x-y+z=3
-------------
  3x+2z=9
->3x=9-2z (1)

3x-z=0
3x=z (2)

From (1)+(2)-> z=9-2z
solve for z
-3z=9
z=-3 (3)

plug (3) in (2)
->3x=-3
->x=-1 (4)

Plug (3) and (4) in <span>x+y+z=6
</span>-3+y+(-3)=6
solve for y
y-6=6
->y=12
Answer:
x=-1
y=12
z=-3


andrew-mc [135]3 years ago
4 0
The answer to the problem is (1, 2, 3).
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Explanation:

First, let's call the number we are going to solve for "x".

Then two thirds of this number can be written as:

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