Solve the system of linear equations and check any solution algebraically

2 answers:

6 0

It is pretty long, hope you understand
x+y+z=6
+
2x-y+z=3
-------------
3x+2z=9
->3x=9-2z (1)

3x-z=0
3x=z (2)

From (1)+(2)-> z=9-2z
solve for z
-3z=9
z=-3 (3)

plug (3) in (2)
->3x=-3
->x=-1 (4)

Plug (3) and (4) in <span>x+y+z=6
</span>-3+y+(-3)=6
solve for y
y-6=6
->y=12
Answer:
x=-1
y=12
z=-3

andrew-mc [135]3 years ago

4 0

The answer to the problem is (1, 2, 3).

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