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DedPeter [7]
3 years ago
14

The ratio of dogs to cats at the shelter is 5 to 6. If the total number of dogs and cats combined at the shelter is 132, then ho

w many cats are at the shelter?
Mathematics
1 answer:
kati45 [8]3 years ago
6 0

Answer:

Let's set up an equation with x as the number of times 5 and 4 are being multiplied (remember that 5:4 is a ratio, we don't know how many dogs and cats there are, just that the ratio of dogs to cats is 5:4):

5x+4x=153

9x=153

x=17

4x=4⋅17=68

There are 85 dogs (5⋅17) and 68 cats (85:68=5:4)

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Dafna11 [192]

Step-by-step explanation:

3x + 5 = 36

3x = 36 - 5 = 31 (subtract 5 on both sides)

3x = 31

x = 31/3 (divide 3 on both sides)

Hence x = 31/3.

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3 years ago
At 1pm there are 16 seagulls at 3pm there are 40 how many increased in 2 hours
Kobotan [32]

Answer:

24

Step-by-step explanation:

40-16=24   ( brainlist? ) and your welcome!

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What are the coordinates of the imageof point A (2, -7) under the transalition (x,y) (x- 3, y 5)
jenyasd209 [6]

Answer:

The coordinates of the image of point A (2, -7) are A'(-1,-2).

Step-by-step explanation:

Note: The sign is missing between y and 5 in the rule of transitional.

Consider the rule of translation is

(x,y)\Rightarrow (x-3,y+5)

We need to find the image of point A (2, -7).

Substitute x=2 and y=-7 in the above rule.

A(2,-7)\Rightarrow A'(2-3,-7+5)

A(2,-7)\Rightarrow A'(-1,-2)

Therefore, the coordinates of the image of point A (2, -7) are A'(-1,-2).

4 0
3 years ago
What is 67.50 with 5 percent sales tax
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6 0
3 years ago
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The average performance rating of the employees at Company A is 6.5 on a scale from 1 to 10 (10 being highest). The standard dev
djyliett [7]

Answer:

The best choice would be hiring a random employee from company A

Step-by-step explanation:

<em>Supposing that the performance rating of employees follow approximately a normal distribution on both companies</em>, we are interested in finding what percentage of employees of each company have a performance rating greater than 5.5 (which is the mean of the scale), when we measure them in terms of z-scores.

In order to do that we standardize the scores of both companies with respect to the mean 5.5 of ratings

The z-value corresponding to company A is

z=\frac{\bar x-\mu}{s}

where

\bar x = mean of company A

\mu = 5.5 (average of rating between 1 and 10)

s = standard deviation of company A

z=\frac{\bar x-\mu}{s}=\frac{6.5-5.5}{2.1}=0.7142

We do the same for company C

z=\frac{\bar x-\mu}{s}=\frac{7.4-5.5}{6.8}=0.2794

This means that 27.49% of employees of company C have a performance rating > 5.5, whereas 71.42% of employees of company B have a  performance rating > 5.5.

So, the best choice would be hiring a random employee from company A

4 0
3 years ago
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