5 times as many. Since dog B has 2 and dog A has 10, A = 2 * X, since you’re solving for the multiplication comparison. 10/2 = 5, so you’ve got 5 times as many.
I did the work for you. I also showed my work. Hope it helped
Answer:
#1: x/4 - 3/4
#2: x/14 + 9/2
Step-by-step explanation:
because i said so, you should mark me brainliest
Answer:
- The system of equations is x + y = 85 and 7/20x+2/5y=31
- To eliminate the x-variable from the equations, you can multiply the equation with the fractions by 20 and multiply the other equation by -7.
- B-She used 60 minutes for calling and 25 minutes for data.
Step-by-step explanation:
It is always a good idea to start by defining variables in such a problem. Here, we can let x represent the number of calling minutes, and y represent the number of data minutes. The the total number of minutes used is ...
x + y = 85
The total of charges is the sum of the products of charge per minute and minutes used:
7/20x + 2/5y = 31.00
We can eliminate the x-variable in these equations by multiplying the first by -7 and the second by 20, then adding the result.
-7(x +y) +20(7/20x +2/5y) = -7(85) +20(31)
-7x -7y +7x +8y = -595 +620 . . . . eliminate parentheses
y = 25 . . . . . . . . simplify
Then the value of x is
x = 85 -y = 85 -25
x = 60
Answer: $42.56
Step-by-step explanation:
Percent discount in department store = 38%
The regular price of suit = $112.
Price taken off the regular price of the suit =
38% of $112
So, 38% of $112
= (38/100) x $112
= 0.38 x $112
= $42.56
(i.e the customer will pay $112 - $42.56 = $69.44 only for the suit)
Thus, the price taken off the regular price of the suit is $42.56
