Answer:
There is no diagram but
It would be A if you were looking at the endoplasmic reticulum (ER).
It would be B if you were looking at a mitochondrion.
I do not remember what C is, so if it is not the ER, Golgi apparatus, or the mitochondrion, it is most likely C.
It would be D if you were looking at a Golgi apparatus
The salivary glands, stomach, and pancreas secrete<u> lipase enzymes</u> to break down triglycerides into monoglycerides, fatty acids, and glycerol.
Lipases are a set of water-soluble enzymes that hydrolyze substrates such as triglycerides and phospholipids, have a similar structure and are essential in the metabolism of lipoproteins and lipids.
That is, the function of lipase enzymes is to hydrolyze triglycerides to generate diglycerides, monoglycerides, fatty acids and glycerol.
<u>About lipase enzymes</u>:
- It acts on the neutral fats in the diet, splitting them into triglycerides or diglycerides and these to monoglyceride, which is the most easily absorbed fatty compound.
- The action of lipase is much more manifest on triglyceride, and it is also much faster the higher the molecular weight of the fatty acid present.
- It acts on the surface and in an aqueous medium, the emulsifying agent represented by bile salts is essential for optimum effectiveness.
- They are widely distributed, with a presence in the animal and plant kingdoms and even in the simplest unicellular organisms.
Therefore, we can conclude that the salivary glands, stomach, and pancreas secrete lipase enzymes to break down triglycerides into monoglycerides, fatty acids, and glycerol.
Learn more here: brainly.com/question/15737562
Answer:
Since genes come in more than one version, an organism can have two of the same alleles of a gene, or two different alleles. This is important because alleles can be dominant, recessive, or codominant to each other. I hope this helps
Answer: hydrolysis of intermediate palmitoyl Co A ,with loss of labeled CoA.before reaching the matrix gives the answer
Explanation:
This is because when the labeled Coenzyme A of the Plamitate combines as Palmitoy-CoA with oxaloacetate to form intermediate (palmitoyl-CoA )in Citric Acid cycle:
CoA is hydrolysed with loss of the labelled CoA which returns to the cystosol. Therefore, the labelled CoA does not reach the matrix of the mitochondrial,but returns to the Cystosol.
Consequently, the CoA in the Cystosol will be labelled in palmitoylCoA and the one in the matrix of the liver mitochondrial will be non radioactive(,will not labelled).
Answer:
The effect of an external physical factor on cell division is clearly seen in density-dependent inhibition, a phenomenon in which crowded cells stop dividing. ... When cells have formed a complete single layer, they stop dividing (density-dependent inhibition).
Explanation:
