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solniwko [45]
3 years ago
12

Simon has a farm and has to buy a certain amount of feed for each animal. He buys feed once a month and counts all of his animal

s to see how much feed he needs to buy. Chicken feed is about $0.5 per chicken, each horse eats about $5 worth of feed, and goats eat about $4 worth of feed. What equation should he use to find how much he should spend on feed?
A. 0.50 +5h + 4g = total spent on feed
B. 9.5a = total spent on feed
C. 0.50 +5h + 40 = 100
D. 0.59 +49 +5g = total spent on feed​
Mathematics
2 answers:
jolli1 [7]3 years ago
3 0

Answer:

A

Step-by-step explanation:

youre looking for the total spent, and then each variable from the word equation

ki77a [65]3 years ago
3 0

Answer:It is B because you add 5+4 and you get 9 and than you have 9 you have 5 cences

so it is $9.05

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An anthropologist wishes to estimate the average height of men for a certain race of people. If the population standard deviatio
mario62 [17]

Answer:

The probability that the difference between the sample mean \bar{x} and the true population mean \mu is : P[|\bar{x}-\mu|\leq0.7]=0.9876

Step-by-step explanation:

Given :

Population standard deviation \sigma=2.8.

Sample size n=100

The sample mean standard deviation=\frac{\sigma}{\sqrt{n}}

To find :

The probability that the difference between the sample mean \bar{x} and the true population mean \mu

\because\frac{\sigma}{\sqrt{n}}=\frac{2.8}{\sqrt{100}}=\frac{2.8}{10}=0.28

Now, the probability that the difference between the sample mean \bar{x} and the true population mean \mu is :

  P[|\bar{x}-\mu|\leq0.7], nis large \Rightarrow \frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}=z

\Rightarrow P[\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}

\Rightarrow P[z

\Rightarrow P[-2.5

Therefore, the probability P[|\bar{x}-\mu|\leq0.7]=0.9876

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3 years ago
29. Shona earned $44.00, spent $23.00, loaned her brother $5.00,
alexandr402 [8]

Answer: $42.00

Step-by-step explanation:

44-23=21

21-5=16

16+26=42

5 0
3 years ago
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Brandy took 3 friends out for dinner. The cost of the meal was 46.15 she left the 20% tip what was the total cost including the
slega [8]

Answer: $55.35


Step-by-step explanation:

if the bill is $46.15, round it up to $46. Twenty percent of that is $9.20, found by moving the decimal point one place left. Add $9.20 to $46.15, and you get $55.35

i hope this is correct and it helps :)

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3 years ago
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Solve for x. x = [?] = 5x - 73x + 27 Enter​
alexandr402 [8]

When we use the equals sign (=), we indicate that two expressions are equal in value. This is called an equation. For example,  is an equation. By choosing certain procedures, you can go step by step from a given equation to the equation  = some number. The number is the solution to the equation.

 One of the first procedures used in solving equations has an application in our everyday world. Suppose that we place a -kilogram box on one side of a seesaw and a -kilogram stone on the other side. If the center of the box is the same distance from the balance point as the center of the stone, we would expect the seesaw to balance. The box and the stone do not look the same, but they have the same value in weight. If we add a -kilogram lead weight to the center of weight of each object at the same time, the seesaw should still balance. The results are equal.

 There is a similar principle in mathematics. We can state it in words like this.

The Addition Principle

If the same number is added to both sides of an equation, the results on each side are equal in value.

We can restate it in symbols this way.

For real numbers a, b, c if a=b thenat+tc=b+ec

Here is an example.

If

, then

Since we added the same amount  to both sides, each side has an equal value.

We can use the addition principle to solve an equation.

EXAMPLE 1 Solve for .   

  Use the addition principle to add   to both sides.

  Simplify.

  The value of  is .

 We have just found the solution of the equation. The solution is a value for the variable that makes the equation true. We then say that the value, , in our example, satisfies the equation. We can easily verify that  is a solution by substituting this value in the original equation. This step is called checking the solution.

Check.    =

         ≟

         =   ✔

 When the same value appears on both sides of the equals sign, we call the equation an identity. Because the two sides of the equation in our check have the same value, we know that the original equation has been correctly solved. We have found the solution.

 When you are trying to solve these types of equations, you notice that you must add a particular number to both sides of the equation. What is the number to choose? Look at the number that is on the same side of the equation with , that is, the number added to . Then think of the number that is opposite in sign. This is called the additive inverse of the number. The additive inverse of  is  . The additive inverse of   is . The number to add to both sides of the equation is precisely this additive inverse.

 It does not matter which side of the equation contains the variable. The  term may be on the right or left. In the next example the x term will be on the right.

EXAMPLE 2 Solve for .   

  Add  to both sides, since  is the additive inverse of  . This will eliminate the   on the right and isolate .

  Simplify.

  The value of  is .

Check.    =

         ≟   Replace  by .

         =   ✔   Simplify. It checks. The solution is .

 Before you add a number to both sides, you should always simplify the equation. The following example shows how combining numbers by addition separately, on both sides of the equation—simplifies the equation.

EXAMPLE 3 Solve for .   

  Simplify by adding.

  Add the value   to both sides, since   is the additive inverse of .

  Simplify. The value of  is .

Check.    =

         ≟    Replace  by  in the original equation.

           ✔    It checks.

 In Example 3 we added   to each side. You could subtract  from each side and get the same result. In earlier lesson we discussed how subtracting a  is the same as adding a negative . Do you see why?

 We can determine if a value is the solution to an equation by following the same steps used to check an answer. Substitute the value to be tested for the variable in the original equation. We will obtain an identity if the value is the solution.

EXAMPLE 4 Is  the solution to the equation  ? If it is not, find the solution.

We substitute  for  in the equation and see if we obtain an i

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