Answer:
171 newspapers.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 150, \sigma = 25](https://tex.z-dn.net/?f=%5Cmu%20%3D%20150%2C%20%5Csigma%20%3D%2025)
How many newspapers should the newsstand operator order to ensure that he runs short on no more than 20% of days
The number of newspapers must be on the 100-20 = 80th percentile. So this value if X when Z has a pvalue of 0.8. So X when Z = 0.84.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![0.84 = \frac{X - 150}{25}](https://tex.z-dn.net/?f=0.84%20%3D%20%5Cfrac%7BX%20-%20150%7D%7B25%7D)
![X - 150 = 0.84*25](https://tex.z-dn.net/?f=X%20-%20150%20%3D%200.84%2A25)
![X = 171](https://tex.z-dn.net/?f=X%20%3D%20171)
So 171 newspapers.
Answer:B
Step-by-step explanation:
Tenemos precio de lista de $25 para el libro.
Si aplicamos un descuento del 25%, este descuento representa:
![D=(\frac{25}{100})\cdot25=0.25\cdot25=6.25](https://tex.z-dn.net/?f=D%3D%28%5Cfrac%7B25%7D%7B100%7D%29%5Ccdot25%3D0.25%5Ccdot25%3D6.25)
Ahorramos $6.25.
El precio que pagamos el libro es $18.75.
The top right graph
Hope this helps <3
Yes because of you find the gcf for 9 and 15, the answer would be 3 so the asnwer is still odd.