3. (t^2) - 4
4. (1/5)*s + 4
Hello there!
3x - y = 3
-x + y = 3
We need to solve 3x - y = 3 for y
Let start by adding -3x to both sides
3x - y = 3
3x - 3x - y = 3 - 3x
-y = 3 - 3x
We cannot leave the variable with a negative sign. We must multiply both sides by -1
-y * -1= (3 - 3x)-1
y = 3x - 3
Substitute 3x -3 for y in -x+y=3
-x + y = 3
-x + 3x - 3 = 3
2x - 3 = 3
2x = 3 + 3
2x = 6
x = 6/2
x = 3
Now substitute 3 for x in y=3x -3
y = 3x - 3
y = 3(3) - 3
y= 9 - 3
y= 6
Thus,
The answer is x=3 and y=6
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Answer:
x = 1 is not a solution to the equation
Step-by-step explanation:
2x + 4 = -3x - 2 x = 1
2(1) + 4 = -3(1) - 2
2 + 4 = -3 - 2
6 = -5 FALSE
(-1, 2)
So the original point is (3, 4), when you move to the left or right, it changes the x value. When moving it to the right, you add the amount. When moving to the left, you subtract the amount
So after translating the point 4 units to the left, it should be (-1, 4).
Now, you have to move down. When moving up and down, you add or subtract to the y value. When moving up, you add to the amount. When moving down, you subtract the amount.
After subtracting 2, you should be at (-1, 2)
