Answer: P(x ≥ 1) = 0.893
Step-by-step explanation:
We would assume a binomial distribution for the outcome of the investment. The formula is expressed as
P(x = r) = nCr × p^r × q^(n - r)
Where
x represent the number of successes.
p represents the probability of success.
q = (1 - r) represents the probability of failure.
n represents the number of trials or sample.
From the information given,
p = 36% = 36/100 = 0.36
q = 1 - p = 1 - 0.36
q = 0.64
n = 5
Therefore,
P(x ≥ 1) = 1 - P(x = 0)
P(x = 0) = 5C0 × 0.36^0 × 0.64^(5 - 0)
P(x = 0) = 1 × 1 × 0.107
P(x = 0) = 0.107
P(x ≥ 1) = 1 - 0.107 = 0.893
Factor the equation. Remember the value should add to the b value and multiply to the c value.
x^2-x-12= 0
(x-4)(x+3)=0
Use the zero product property to find roots
x-4=0
x=4
x+3=0
x=-3
Final answer: x=-3, x=4
Answer:
y - 2 = - 5(x - 7)
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Here m = - 5 and (a, b) = (7, 2) , thus
y - 2 = - 5(x - 7) ← equation in point- slope form
Answer:
Step-by-step explanation:
L = 3*w + 1 Given
P = 2*(L + w) Formula for Perimeter. Substitute for L
P = 2*(3w + 1 + w) Combine
P = 2*(4w + 1)
P = 58 Given
58 = 8w + 2 Remove the brackets
58 - 2 = 8w Subtract 2
56 = 8*w Divide by 8
56/8 = w
7 = w
================
Find L
L = 3*w + 1
L = 3*7 + 1
L = 22
================
Check
2L + 2W = 58
2*22 + 2*7 =? 58
44 + 14 = ? 58
58 = 58
The answer checks.
Answer:
<u>Option </u><u>D</u> (y = 5/6x -12).
Step-by-step explanation:
Hey there!
The equation of the line which passes through the point (12,-2) is (y+2) = m2(x-12)………(i) [Using one point formula].
According to the question, the first line passes through point (12,6) and (0,-4).
So,



Therefore, the slope of the line is 5/6.
Now as per the condition of parallel lines, m1 =m2 = 5/6.
So, keeping the value of m2 in equation (i), we get;
(y+2) = 5/6(x-12)

or, y = 5/6x - 12.
Therefore, the required equation is y = 5/6 X - 12.
<u>Hope</u><u> </u><u>it </u><u>helps</u><u>!</u>