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3 years ago

On a piece of paper, graph y+237x-1. Then determine which answer choice matches the graph you drew.

Mathematics

1 answer:

Yuri [45]3 years ago

8 0

Answer:

Option A is correct

Step-by-step explanation:

Hope it is helpful....

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I need what is the slope of the line graphed

pentagon [3]

Answer:

-3/5

Step-by-step explanation:

3 0

2 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

$BC^2=BD\cdot AB.$

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

$x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.$

Take positive value x. You get

$AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.$

2. According to the previous theorem,

$AC^2=AD\cdot AB.$

Then

$AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

Answer: $AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

$CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D$

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0

3 years ago

Read 2 more answers

Someone help me with thiss

Airida [17]

Answer:

Step-by-step explanation:

All angles in the triangle will equal to 180

Angle A = 180-98-46

A=36

8 0

2 years ago

Read 2 more answers

The First aircraft has 80 more seats than the second aircraft. The third aircraft has 61 fever seats than the second aircraft. i

kotykmax [81]

Step-by-step explanation:

b=a-80

c=b-61

c=a-141

a+b+c=3a-221=430

3a=651

a=217 & b =137 & c=76

3 0

3 years ago

Triangle Proofs Please help

oksian1 [2.3K]

Explanation:

There may be a more direct way to do this, but here's one way. We make no claim that the statements used here are on your menu of statements.

<u>Statement</u> . . . . <u>Reason</u>

2. ∆ADB, ∆ACB are isosceles . . . . definition of isosceles triangle

3. AD ≅ BD

and ∠CAE ≅ ∠CBE . . . . definition of isosceles triangle

4. ∠CAE = ∠CAD +∠DAE

and ∠CBE = ∠CBD +∠DBE . . . . angle addition postulate

5. ∠CAD +∠DAE ≅ ∠CBD +∠DBE . . . . substitution property of equality

6. ∠CAD +∠DAE ≅ ∠CBD +∠DAE . . . . substitution property of equality

7. ∠CAD ≅ ∠CBD . . . . subtraction property of equality

8. ∆CAD ≅ ∆CBD . . . . SAS congruence postulate

9. ∠ACD ≅ ∠BCD . . . . CPCTC

10. DC bisects ∠ACB . . . . definition of angle bisector

4 0

2 years ago