Answer:
The standard form of the quadratic equation is x² + 3·x - 4 = 0
Step-by-step explanation:
The standard form of a quadratic equation is a·x² + b·x + c = 0
Given that the expression of the quadratic equation is (x + 4)·(x - 1) = y, we can write the given expression in standard form by expanding, and equating the result to zero as follows;
(x + 4)·(x - 1) = x² - x + 4·x - 4 = x² + 3·x - 4 = 0
The standard form of the quadratic equation is x² + 3·x - 4 = 0
The graph of the equation created with MS Excel is attached
There Is no picture so I can see what you are talking about
C. 21,525 < 22,789 hope this helps
Answer:
y = 3x -5
Step-by-step explanation:
Use the slope-intercept form:
y = (slope)x + intercept
slope = 3
intercept = -5
Equation in slope-intercept form:
y = 3x -5
Hello:
f(x) =6sin(x)
f'(x) = 6 cos(x)
the equation of the tangent line is : y=f'(π/6)(x-π/6)+f(<span>π/6)
f'(</span>π/6)=6cos(π/6)=6×(√3/2)=3<span>√3
f(</span>π/6) =3
the equation is : y = 3√3(x-π/6)+3