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Pie
3 years ago
9

4(n-1)+2 = -23 +7n

Mathematics
1 answer:
liubo4ka [24]3 years ago
6 0

Answer:

<h2><em><u>n</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em></h2>

Step-by-step explanation:

4(n-1)+2 = -23 +7n

=> 4n - 4 + 2 = - 23 + 7n

=> 23 - 4 + 2 = 7n - 4n

=> 21 = 3n

=  > n =  \frac{21}{3}

=> <em><u>n</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

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10x+20=7x-8<br><br> Solve for x.
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Step-by-step explanation:

Isolate the variable

10x - 7x = -20 - 8

3x = -28

x = -9.333333333333

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3 years ago
At the beginning of the year agent savings account balance was $28. Each week he deposits another $15 into that account and it d
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Account balance is not proportional to the number of weeks.
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Katen [24]

Answer:

4-3=1

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Step-by-step explanation:

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2 years ago
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URGENT MATH HELP BRAINLIEST
Lelechka [254]

Answer:

Step-by-step explanation:

a. This is a right triangle with two sides and one angle given.

-We apply Sine Rule to find the angle B:

\frac{a}{Sin \ A}=\frac{b}{Sin \ B}=\frac{b}{Sin \ C}

-The sides given are 10and 17 and the right angle 90°

\frac{17}{Sin \ 90 \textdegree}=\frac{10}{Sin \ m\angle B}\\\\m\angle B=Sin^{-1}\frac{10}{(17/Sin \ 90\textdegree)}\\\\=36.03\textdegree

Hence  the angle B is 36.03°

b.We again use the sine rule to obtain the unknown angle w:

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\frac{a}{Sin \ a}=\frac{b}{Sin \ B}\\\\\frac{15}{Sin \ 90\textdegree}=\frac{9}{Sin \ w\textdegree}\\\\\\\\w=Sin^{-1}(\frac{9}{15}), \ \ Sin \ 90\textdegree=1\\\\=36.87\textdegree

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4 0
3 years ago
1. Writing an equation for an exponential function by
Naya [18.7K]

Answer: 1) t(n)=0.6(2)^n

2) f(x)=10(5)^x

Step-by-step explanation:

1) Let the function that shows the thickness of the paper after n folds,

t(n) = ab^n         ---------(1)

Since, According to the question,

Initially the thickness of the paper = 0.6

That is, at n = 0, t(0) = 0.6

By equation (1),

0.6 = a(b)^0\implies 0.6 = a

Hence the function that shows the given situation,

t(n) = 0.6 b^n       -----------(2)

Again when we fold the paper the thickness of the paper will be doubled.

Thus, at n = 1, t(1) = 1.2

By equation (2),

1.2 = 0.6 b^1\implies 2 = b

Thus, the complete function is,

t(n) = 0.6 (2)^n    

2) Let the function that is passing through the points (-2, 2/5) and (-1,2),

f(x) = ab^x         ---------(1)

For f(x) = 2, x = -1

By equation (1),

2= ab^{-1}       ---------(2)

Also, For f(x) = 2/5, x = -2

Again, By equation (1),

\frac{2}{5}= a(b)^{-2}

\implies \frac{2}{5}=ab^{-1}b^{-1}=2b^{-1}

\implies \frac{2}{5}=\frac{2}{b}

\implies 2b=10

\implies b = 5

By substituting this value in equation (2),

We get, a = 10

Hence, from equation (1), the function that is passing through the points (-2, 2/5) and (-1,2),

f(x) = 10(5)^x

5 0
3 years ago
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