<span> the new way of </span>removing duplicates<span> from an iterable while keeping it in the original order </span>
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Answer:
The complete method is as follows:
public static int divBySum(int[] arr, int num){
int sum = 0;
for(int i:arr){
if(i%num == 0)
sum+=i;
}
return sum;
}
Explanation:
As instructed, the program assumes that arr has been declared and initialized. So, this solution only completes the divBySum method (the main method is not included)
This line defines the method
public static int divBySum(int[] arr, int num){
This line declares and initializes sum to 0
int sum = 0;
This uses for each to iterate through the array elements
for(int i:arr){
This checks if an array element is divisible by num (the second parameter)
if(i%num == 0)
If yes, sum is updated
sum+=i;
}
This returns the calculated sum
return sum;
}
