Answer:
Hello! The answer to your question is function I had the same question and got it right!
Explanation:
Hope this helped:)
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Answer:
public static void removeInRange(List<Integer> list, int value, int start, int end) {
for (int i = end - 1; i >= start; i--) {
if (list.get(i) == value) {
list.remove(i);
}
}
System.out.println(list);
}
Explanation:
- Create a method named <em>removeInRange</em> that takes four parameters, a list, an integer number, a starting index and an ending index
- Inside the method, initialize a <u>for loop</u> that iterates between starting index and ending index
- If any number between these ranges is equal to the given <em>value</em>, then remove that value from the list, using <u>remove</u> method
- When the loop is done, print the new list
Answer:
RESET...
Explanation:
.The file is not Indexed for searches.
.The file can only be viewed.
.The file is ready for backup.
.The file or folder is hidden.
√ Reset
.Next
Answer:
Data at the following addresses will be as following:-
200 :- 34
201 :- 12
202 :- 78
203 :- 56
Explanation:
If there is 1 byte storage.
if the data is of 4 digits.Then we have to store it in 2 memory locations.
The first two digits will be stored at the higher byte address that is 201 and the last two digits will be stored at then lower byte address that is 200.
The case is same with the next data 5678.
At address 202 :- 78 will be stored and at address 203 :- 56 will be stored.
