To find it, evaluate it at the endpoints and the vertex
in form
f(x)=ax²+bx+c
the x value of the vertex is -b/2a
given
c(t)=1t²-10t+76
x value of vertex is -(-10)/1=10
evaluate c(0) and c(13) and c(10)
c(0)=76
c(13)=115
c(10)=76
it reached minimum in 2000 and 2010
porbably teacher wants 2010
the min value is $76
We would have to see the square to determine that
Answer:
-3
Step-by-step explanation:
Answer:
= 4sqrt3
Step-by-step explanation:
-2i sqrt -12
= -2i * i sqrt12 <-- i^2 = -1
= -2i^2sqrt12
= -2(-1)sqrt12
= 2sqrt12
= 2 * 2 sqrt3
= 4sqrt3
Answe: 3rd one
Step-by-step explanation:
