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Tpy6a [65]
3 years ago
15

X^3 -2mx^2 +16 (x+2)PLS ANSWER FASTI WILL MARK YOU THE BRANLIEST

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
5 0
X^3mx^2+16
3*2=5
Mx^5+16
X+2 has no like terms
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Help please
yawa3891 [41]

Answer:

C. 4.6

Step-by-step explanation:

If you subtract 3.0 from 1.4 you get 1.6, which is the can be added to 3.0 to find the missing value.

8 0
3 years ago
all of the sides of the hexagon has the same length s. which expression represents the perimeter of this hexagon
Sphinxa [80]

Answer:

6s

Step-by-step explanation:

6 0
3 years ago
Use the binomial expression (p+q)^n to calculate a binomial distribution with n=5 and p=0.3.(Show all steps)
Helen [10]

Answer:

The binomial in expanded form is (0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}.

Step-by-step explanation:

The Binomial Theorem states that a binomial of the form (a + b)^{n} can be expanded by using the following identity:

(a + b)^{n} = \Sigma \limits^{n}_{k = 0}\,\frac{n!}{k!\cdot (n-k)!}\cdot a^{n-k}\cdot b^{k} (1)

If we know that a = p = 0.3 and n = 5, then the expanded form of the binomial is:

(p+q)^{n} = \frac{243}{100000} + 5\cdot \left(\frac{81}{10000} \right)\cdot q + 10\cdot \left(\frac{27}{1000})\cdot q^{2} + 10\cdot \left(\frac{9}{100} \right)\cdot q^{3} + 5\cdot \left(\frac{3}{10} \right)\cdot q^{4} + q^{5}

(0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}

8 0
3 years ago
7^2 + 3[81 – (4x6)] please help me!!!!!!!!
Anastaziya [24]

Answer:220

Step-by-step explanation:Simplify

4 0
4 years ago
17 divided by 6294 idk what it is helllp
Oliga [24]
Ummmmm is that the question or is there other numbers
7 0
3 years ago
Read 2 more answers
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