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xenn [34]
3 years ago
13

Please someone help me solve!

Mathematics
2 answers:
Serga [27]3 years ago
7 0
The second will have a greater value
makkiz [27]3 years ago
5 0
First one,3+(2+5) second one,3x(2+5), 3x(2+5) has a greater value

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Find the value of A in the formula A=1/2h(a+b) when h=6inches, a=12inches, and b=8inches.
Arada [10]

Answer:

<h2>A = 60 in²</h2><h2 />

Step-by-step explanation:

a = 12 in

b = 8 in.

h = 6 in.

<u>plugin values into the formula:</u>

A = 1/2 h(a + b)

A = <u>(12 + 8) </u>  x  6

           2

A = 60 in²

8 0
3 years ago
PLS HELP HAS TO BE CORRECT
katovenus [111]

Answer:

○ 4⁵\4²

Step-by-step explanation:

1. According to the Quotient-to-Power Exponential Rule, whenever you divide terms with exponents and coefficients, you subtract the exponents:

4²\4⁵ = 4⁻³

3. According to the Negative Exponential Rule [Reverse], you bring the denominator to the numerator while ALTERING THE INTEGER SYMBOL FROM POSITIVE TO NEGATIVE:

b⁻ⁿ = 1\bⁿ

However, according to the Negative Exponential Rule, you bring the denominator to the numerator while ALTERING THE INTEGER SYMBOL FROM NEGATIVE TO POSITIVE:

bⁿ = 1\b⁻ⁿ

Anyway, this is what you get using this exponential:

1\4³ = 4⁻³

4. Back to what I said about the <em>Quotient-to-Power</em> Exponential Rule, you subtract the exponents, but in this case, doing that will give you 4³. This is the ONLY uniqueness, while the rest of them are 4⁻³.

I am joyous to assist you anytime.

3 0
3 years ago
Y=[[x]]<br> evaluate this function at x=3
dedylja [7]

Step-by-step explanation:

Solution

y=[[x]], at x=3,

therefore the function of y = 3

you can merge 3,3

7 0
3 years ago
Can someone help me simplify these expressions
Sunny_sXe [5.5K]

Step-by-step explanation:

4. Let's multiply the coefficients. 2 * 6 * (-5) = -60. As for the exponents, since they have the same base we'll just add the exponents giving us s^(2 + 1 + 4) = s^7 so the answer is -60s^7.

7. -2/3 * -1/2 * -4 = -4/3 and the exponent is b^(2 + 3 + 4) = b^9 so the answer is -4/3b^9

4 0
3 years ago
How are these triangles congruent?
ICE Princess25 [194]

Answer:

\triangle PTY \cong \triangle PSQ by ASA

Step-by-step explanation:

In triangle PTU and triangle PSQ

\overline{PT} \cong \overline{PS}     [Side]             [Given]

\angle PTU \cong \angle PSQ          [Angle]

Vertical angles are those angles which are opposite to each other.

\angle TPU \cong \angle SPQ        {Angle]

ASA(Angle-Side-Angle) postulates states if two angles and one included  side of one triangle are congruent to two angles and the included side of the other triangle, then these triangle are congruent.

by ASA postulates;

\triangle PTY \cong \triangle PSQ


5 0
4 years ago
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