Given:$7/child
$10/adult
Total people = 700
Total money = $6,400
First, make two equations.
Let a = # of adults & Let c = # of children.
Let p = total people
1. a+c = 700
2. 10a+7c = 6,400
Then, rearrange the equation to solve for a variable.
c = 700-a
Substitute (700-a) for c, or the # of children in the second equation.
10a+(700-a) = 6400
9a+700 = 6400
9a+700-700 = 6400-700
9a = 5700
9a/9 = 5700/9
a = 633
= # of adults attended700-633
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= c =
66
= # of children attended
Answer:
The largest possible number of x intercept is 9 while the largest possible number of relative max/min is 8
Step-by-step explanation:
For any polynomial of degree n with distinct and real solutions, it can have at most n different x intercepts. This would imply it can have at most 9 distinct real solutions.
It can also have at most n-1 relative max/min in alternating order. This is best illustrated when such polynomial is sketched on a graph.
For example a quadratic expression is a polynomial of degree 2 and has at most 2 distinct solutions and 1 relative max/min.
In this question, for the polynomial, its degree (n) = 9
So it can have at most 9 x intercepts and at most 8 relative max/min.
Answer:
4x+x=40
5x+40
x=8
8, 32
Step-by-step explanation:
Answer:
The answer is 10
Step-by-step explanation:
a + 5 =15
15-5=10
Answer:
y=-x+5
Step-by-step explanation:
(4,1)
(8,-3)
1)a slope of a line is (y2-y1)/(x2-x1)
so (-3-1)/(8-4)
-4/4=>m=-1
2)to find y-int replace any points in the equation by x and y
so 1=-1(4)+b
1=-4+b
1+4=b
so b= 5
therefore the equation is y=-x+5 so d