Rewrite log2^8=3 in exponential form

Angle ABC is inscribed in a circle as shown.<br><br>What is the measure, in degrees, of angle ABC?

sladkih [1.3K]

Answer

Find out the measure, in degrees, of angle ABC .

To prove

The relationship between inscribed angles and their arcs

The measure of an inscribed angle is half the measure the intercepted arc.

The formula is

$Measure\ of\ inscribed\ angle = \frac{1}{2}\times measure\ of\ intercepted\ arc$

As given in the diagram

The measure of the intercepted arc A to B is 120°.

Put value in the formula

$\angle ABC = \frac{1\times 120^{\circ}}{2}$

∠ABC = 60°

Therefore the measure of the ∠ABC is 60° .

5 0

3 years ago

BRAINLIEST AND HIGH POINTS :D

castortr0y [4]

Answer:

A) (2x+15)=65=180°

Step-by-step explanation:

Hey there!

It's a straight line, which means that the sum will be 180°.

So, (2x+15)=65=180°

~

Hope this helps!

6 0

2 years ago

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Given f(x)=-2x-1, solve for x when f(x)=-7

Svetlanka [38]

Answer:

The answer is -15.

Step-by-step explanation:

1. 2x - 1

2. 2(-7) - 1

3. (-14) - 1

4. -15

By plugging in our x value, we are able to use PEMDAS to multiply 2 and the value of x and then, we subtract 1 from the value we got from step 3 to get -15.

5 0

2 years ago

can sumone just do number 17 for me thats it, ill give brainlist if correct and plz dont spam me or perposly answer knowing you

rusak2 [61]

Answer: For 17 is x=24

Step-by-step explanation:

5 0

2 years ago

Which equations represent the line that is parallel to 3x − 4y = 7 and passes through the point (−4, −2)? Select two options.

Elanso [62]

Answer:

2 and 5

Step-by-step explanation:

The slope-intercept form of a line is y=mx-b where m is slope and b is y-intercept.

The point-slope form of a line is y-y1=m(x-x1) where m is the slope and (x1,y1) is a point on the line.

The standard form a line is ax+by=c.

So anyways parallel lines have the same slope.

So if we are looking for a line parallel to 3x-4y=7 then we need to know the slope of this line so we can find the slope of our parallel line.

3x-4y=7

Goal: Put into slope-intercept form

3x-4y=7

Subtract 3x on both sides:

-4y=-3x+7

Divide both sides by -4:

$y=\frac{-3}{-4}x+\frac{7}{-4}$

Simplify:

$y=\frac{3}{4}x+\frac{-7}{4}$

So the slope of this line is 3/4. So our line that is parallel to this one will have this same slope.

So we know our line should be in the form of $y=\frac{3}{4}x+b$ .

To find b we will use the point that is suppose to be on our new line here which is (x,y)=(-4,-2).

So plugging this in to solve for b now:

$-2=\frac{3}{4}(-4)+b$

$-2=-3+b$

$3-2=b$

$b=1$

so the equation of our line in slope-intercept form is $y=\frac{3}{4}x+1$

So that isn't option 1 because the slope is different. That was the only option that was in slope-intercept form.

The standard form of a line is ax+by=c and we have 2 options that look like that.

So let's rearrange the line that we just found into that form.

$y=\frac{3}{4}x+1$

Clear the fractions because we only want integer coefficients by multiplying both sides by 4.

This gives us:

$4y=3x+4$

Subtract 3x on both sides:

$-3x+4y=4$

I don't see this option either.

Multiply both sides by -1:

$3x-4y=-4$

I do see this as a option. So far the only option that works is 2.

Let's look at point slope form now.

We had the point that our line went through was (x1,y1)=(-4,-2) and the slope,m, was 3/4 (we found this earlier).

y-y1=m(x-x1)

Plug in like so:

y-(-2)=3/4(x-(-4))

y+2=3/4 (x+4)

So option 5 looks good too.

7 0

3 years ago

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