Question

Our pool is twice as long as it is wide and is surrounded by a walkway of uniform width of 1 foot. The

Answer 1

Step-by-step explanation:

x=width of pool

2x=length of pool

the dimensions of the rectangle forming the walkway and the pool are x+4 and 2x+4

the area of this rectangle minus the area of the pool is 196 square feet

(2x+4)(x+4)-(x)(2x)=196

2x^2+4x+8x+16-2x^2=196

combine similar terms

12x+16=196

12x=196-16

12x=180

x=180/12

x=15 feet is the width of the pool

check: 34*19-30*15=196

646-450=196

196=196