Answer: x < 360
Step-by-step explanation:
Let x be the total cost for the trip.
And, Here the total number of person = 4
Therefore, the cost for each person = x/4
And, According to the question, The cost must below $90 per person.
Therefore, x/4 < 90
⇒ x < 360
Which is the required inequality for the situation.
Answer:
Step-by-step explanation:
Lets Price of a DVD is fixed i.e. 15
and One CD price is 5 (Not fixed)
In First situation
2 DVDs and 1 CD cost = 35 as given
2 x 15 + 5 = 35
Lets one CD price is 7.5
In Second situation
2 x 15 + 2 x 7.5 = 45
Its mean CD price may be between 5 to 7.5
In asked scenario, Martin has 50
1 DVD and 3 CDs?
1 x 15 + 3 x 7.5 = 37.5
37.5 is lesser than 50
Hence Martin has enough to buy 1 DVD and 3 CDs.
Each face of the cube has an equal
probability of being rolled. There are 2 numbers on the cube less than 3 (1 and 2). The event of rolling a 1 and the event of rolling a 2 are mutually exclusive (you can't roll both faces at once), so

Answer:
74°
Step-by-step explanation:
180-106
since supplementary is 180°
The probability that Pete exceeds 200 in at least 9 of his next 10 games is 0.268+0.1074 = 0.3754
<h3>What is Probability ?</h3>
Probability is defined as the likeliness of an event to happen.
It has a range of 0 to 1.
It is given that
Pete, a professional bowler, is unhappy with any game below 200
80% of his games exceed this score.
the probability that Pete exceeds 200 in at least 9 of his next 10 games is given by
P( 9/10 > 200) +P(10/10>200)
The binomial experiment consists of n trial out of it x is success.

Here p = 0.8
For 9/10 matches

For (10/10 >200)

Therefore the probability that Pete exceeds 200 in at least 9 of his next 10 games is 0.268+0.1074 = 0.3754.
To know more about Probability
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