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tatuchka [14]
2 years ago
8

The blue team scored two more than five times the number of points,p, scored by the red team

Mathematics
1 answer:
morpeh [17]2 years ago
8 0

Answer:

2 + 5p

Step-by-step explanation:

Hi there!

Let p equal the number of points scored by the red team.

<u>We're given:</u>

The blue team scored two more than five times the number of points scored by the red team.

⇒ blue team points = 2 + (5 × red team points)

⇒ blue team points = 2 + 5p

I hope this helps!

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Vinil7 [7]

Answer:

y=1/3x -4

Step-by-step explanation:

3y-x=-12

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m=1/3

(gradient is the same since its parallel)

y=mX+c

(2) = 1/3(18) + c

2 = 6 + c

2 - 6 = c

c= -4

(y-intercept)

Therefore: y=1/3x-4

8 0
2 years ago
Given right triangle abc and sin A= 1/2, cos A = √3/2
V125BC [204]

Answer:

true

Step-by-step explanation:

sinA² + cosA²=1

⇔(1/2)² + cosA²=1

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7 0
2 years ago
Express<br> ln3+2lnx <br> as a single logarithm
Naily [24]

Answer:

ln (3x^2)

Step-by-step explanation:

ln3 + 2ln(x)

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4 0
2 years ago
Please help me answer this question
ratelena [41]

By the definition of the hyperbolic function tanh x, we have proven that \frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}

<h3>Hyperbolic functions & Proof of identities </h3>

By definition

tanh \ x=\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}}

Then,

\frac{1-tanh \ x}{1 + tanh \ x}=\frac{1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }{1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }

=1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} \div (1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} })

=\frac{e^{x} +e^{-x}-(e^{x} -e^{-x})}{e^{x} +e^{-x}} \div (\frac{e^{x} +e^{-x}+e^{x} -e^{-x}}{e^{x} +e^{-x}} })

=\frac{e^{x} +e^{-x}-e^{x} +e^{-x}}{e^{x} +e^{-x}} \div \frac{e^{x} +e^{-x}+e^{x} -e^{-x}}{e^{x} +e^{-x}} }

=\frac{e^{-x}+e^{-x}}{e^{x} +e^{-x}} \div \frac{e^{x} +e^{x} }{e^{x} +e^{-x}} }

=\frac{2e^{-x}}{e^{x} +e^{-x}} \div \frac{2e^{x} }{e^{x} +e^{-x}} }

=\frac{2e^{-x}}{e^{x} +e^{-x}} \times \frac{e^{x} +e^{-x}}{2e^{x}}

=\frac{2e^{-x}}{1} \times \frac{1}{2e^{x}}

=\frac{2e^{-x}}{2e^{x}}

=\frac{e^{-x}}{e^{x}}
=e^{-x} \times \frac{1}{e^{x}}

= e^{-x} \times e^{-x}

= e^{-x+-x}

= e^{-x-x}

= e^{-2x}

Hence, we have proven that \frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}

Learn more on Proof of Identities here: brainly.com/question/2561079

#SPJ1

6 0
2 years ago
EXTRA POINTS!!! Write a system of three inequalities that has (2, 1) in the solution set.
Alex17521 [72]
Your system could be anything, just remember that input should be half than the output.

So, y ≥ 1/2x
5y ≥ 5/2x
10y ≥ 5x

Hope this helps!
5 0
3 years ago
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