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Irina-Kira [14]
3 years ago
9

The pressure of earth's atmosphere at sea level is approximately 1000 millibars and decreases exponentially with elevation. At a

n elevation of 30,000ft, the pressure is one-third of the sea level pressure. At what elevation is the pressure half of the sea-level pressure? At what elevation is it 1% of the sea-level pressure?
Mathematics
1 answer:
Flauer [41]3 years ago
3 0
I believe it's 1000 millibars
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skad [1K]

Answer:

\displaystyle d = 4\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
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<u>Algebra I</u>

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<u>Algebra II</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formulas]:                                                     \displaystyle d = \sqrt{(3+5)^2+(2-6)^2}
  2. [Distance] [√Radical] (Parenthesis) Add/Subtract:                                       \displaystyle d = \sqrt{(8)^2+(-4)^2}
  3. [Distance] [√Radical] Evaluate exponents:                                                    \displaystyle d = \sqrt{64+16}
  4. [Distance] [√Radical] Add:                                                                             \displaystyle d = \sqrt{80}
  5. [Distance] [√Radical] Simplify:                                                                         \displaystyle d = 4\sqrt{5}
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