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3 years ago

Find the equation of the line passing through the point (-6,4) that is perpendicular to the line 5x 3y

Mathematics

2 answers:

skad [1K]3 years ago

4 0

Answer:

y= 1/2x + b

Step-by-step explanation:

elena55 [62]3 years ago

3 0

Answer

y=−3/5x−23/5

given the slope m of a line then the slope of a line

perpendicular to it is

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M(-5,9) and N(-2,7) P(-3,-7) and Q(3,-5

jek_recluse [69]

Answer:

M=(4,112)=(4,5.5) A

Step-by-step explanation:

The midpoint for two points P=(px,py) and Q=(qx,qy) is M=(px+qx2,py+qy2).

We have that px=3, py=2, qx=5, qy=9.

Thus, M=(3+52,2+92)=(4,112).

7 0

2 years ago

Explain how the words term and coefficient are used in talking about the algebraic expression.

cupoosta [38]

<h2>Answer:</h2>

The algebraic expressions are composed of several elements: Terms, Coefficients, Signs, Variables and Exponents. In this case we will focus on the first two.

The terms are composed of sign, coefficient, variable and exponent. The terms are separated from each other by the plus sign (+) or the minus sign (-).

For example, in the following expression:

2x-3x

We have two terms separated by the negative sign (-):

2x is the first term

-3x is the second term

Now, the coefficients are the numbers that multiply the variable. Note that if this coefficient is one (1) it is omitted .

For example in the following expression, the variable is x:

2x-3x+x

2 is the coefficient of x in the first term

-3 is the coefficient of x in the second term

1 is the coefficient of x in the third term, but is omitted

In order to understand this in a better way, see the figure attached, where the algebraic expression is composed by one term.

6 0

3 years ago

What is the answer 19=3s+4

krok68 [10]

Answer:

Step-by-step explanation:

hello :

19=3s+4

19-4 = 3s+4-4

3s=15

s=15/3

s=5

5 0

4 years ago

Read 2 more answers

Given sin x =-4/5 and x is in quadrent 3, what is the value of tan x/2

4vir4ik [10]

Answer:

We can write sin x in terms of tan x/2 using the formula:

⇒ sin x = (2 tan (x/2)) / (1 + tan2(x/2))

Therefore, using the above formula, we can find the values of tan x/2 by putting the value of sin x.

⇒ -4/5 = (2 tan (x/2)) / (1 + tan2(x/2))

Now, if we replace tan (x/2) by y, we get a quadratic equation:

⇒ 0.8y2 + 2y + 0.8 = 0

⇒ 2y2 + 5y + 2 = 0

By using the quadratic formula, we get y = -0.5, -2

Hence, the value of tan (x/2) = -0.5, -2

Now, we have two solutions of tan (x/2).

Now, let's check for the ideal solution using the formula tan x = (2 tan (x/2)) / (1 - tan2(x/2)).

For tan (x/2) = -0.5:

⇒ tan x = 2(-0.5) / 1 - (-0.5)2 = -4/3

It is also given that x lies in the third quadrant. We know that tan is positive in the third quadrant, and here we get tan x = -4/3 which is negative.

Hence, we can say that tan (x/2) = -0.5 is not a correct solution. Hence it is rejected.

Now let's check for tan (x/2) = -2.

⇒ tan x = 2(-2) / 1 - (-2)2 = 4/3

Here, we get tan x = 4/3 which is positive.

Hence, we can say that tan (x/2) = -2 is a correct solution.

5 0

3 years ago

Fill the missing values to make the equations true.

taurus [48]

Logarithm properties:

$\displaystyle \log_a b+\log_a c=\log_a (b\cdot c)\\\\\log_ab-\log_a c=\log_a \left( \frac{b}{c} \right)\\\\\log_{a^p}b^q= \frac{q}{p} \log_a b$

According to this, we can get:

$\displaystyle a)\log_7 3+\log_7 8=\log_7 (3\cdot 8)=\log_724\\\\b) \log_89-\log_85=\log_8 \frac{9}{5}\\\\c)\log_325=2\log_35$

3 0

3 years ago