Answer:
a= 74
c= 10
d= 25
e= 10
f=16
g= 90
h= 24
j= 26
k= 154
m= 70
n= 170
p= 156
r= 154
s= 129
t= 148
v= 55
w= 41
x= 55
y= 24
z= 106
Step-by-step explanation:
Answer:
$57,500
Step-by-step explanation:
$57,500
Answer:
15 miles
Step-by-step explanation:
pythagorean theorem
9²+12²=x²
x=15 miles
<span>Simplifying
6(x + 1) + 5 = 13 + -2 + 6x
Reorder the terms:
6(1 + x) + 5 = 13 + -2 + 6x
(1 * 6 + x * 6) + 5 = 13 + -2 + 6x
(6 + 6x) + 5 = 13 + -2 + 6x
Reorder the terms:
6 + 5 + 6x = 13 + -2 + 6x
Combine like terms: 6 + 5 = 11
11 + 6x = 13 + -2 + 6x
Combine like terms: 13 + -2 = 11
11 + 6x = 11 + 6x
Add '-11' to each side of the equation.
11 + -11 + 6x = 11 + -11 + 6x
Combine like terms: 11 + -11 = 0
0 + 6x = 11 + -11 + 6x
6x = 11 + -11 + 6x
Combine like terms: 11 + -11 = 0
6x = 0 + 6x
6x = 6x
Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x
Combine like terms: 6x + -6x = 0
0 = 6x + -6x
Combine like terms: 6x + -6x = 0
0 = 0
Solving
0 = 0
Couldn't find a variable to solve for.
This equation is an identity, all real numbers are solutions.</span>
Answer:
20.6
Step-by-step explanation:
Given data
J(-1, 5)
K(4, 5), and
L(4, -2)
Required
The perimeter of the traingle
Let us find the distance between the vertices
J(-1, 5) amd
K(4, 5)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((4+1)²+(5-5)²)
d=√5²
d= √25
d= 5
Let us find the distance between the vertices
K(4, 5), and
L(4, -2)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((4-4)²+(-2-5)²)
d=√-7²
d= √49
d= 7
Let us find the distance between the vertices
L(4, -2) and
J(-1, 5)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((-1-4)²+(5+2)²)
d=√-5²+7²
d= √25+49
d= √74
d=8.6
Hence the total length of the triangle is
=5+7+8.6
=20.6
