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Vera_Pavlovna [14]
3 years ago
6

Help please XD... super confused. (# 2)

Mathematics
1 answer:
Komok [63]3 years ago
5 0
Mean doesn't belong because MAD, Range, and IQR are all in one group
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How can a line segment CD be written using symbols?
kykrilka [37]

Solution

- The line segment CD is written as follows:

\overline{CD}

6 0
2 years ago
What is the area of the shaded region? Use 3.14 for pi and round to the nearest tenth.
natulia [17]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
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Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
4 years ago
What is the calculation of pi
Tpy6a [65]
I hope this helps you



3,14
7 0
3 years ago
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Kamila has a rectangular lawn that measures 80 by 150 feet. She wants to lay gravel made from colored rock in a border, 6 feet w
alex41 [277]

Answer:

1)Diagram attached

2)8424

3)1404

4)1569

Step-by-step explanation:

1)

Diagram is attached

2)

How many square feet of the gravel will surround the lawn:

Converting yards into feet:

1 yard =3 feet

So 80 yard =80(3) feet

                   =240 feet

and 150 yard =150 (3) feet

                     =450 feet

Area of rectangle is given by :length X width

Area of the outer border = (6+ 240+ 6 ) (6+ 450+6)

                                         = 252 X 462

                                         = 116424

Area of the lawn = 240 X 450

                            = 108000

Area of gravel border = 116424 - 108000

                                    = 8424

Area of gravel border is 8424 ft^2

3)

Total volume when depth is 2 inches:

converting inches to feet:

1 inch=  0.083 feet

2 inches =0.1667 feet

volume = base area X depth

            =8424 X 0.1667

            = 1404

 total volume of gravel needed for the border is 1404 ft^3

4)

Given:

A large bag of colored rock contains 5/8 of a cubic yard and costs $30

total cost of the rocks needed for the border=?

1 cubic yard = $30

converting cubic yard to cubic feet

1 cubic yard=27 cubic feet

cost of 1 cubic yard= cost of 27 cubic feet = $ 30

cost of 1 cubic feet=30/27

cost of  1404 cubic feet= 1404 X 30 / 27

                                     = 1560

the total cost of the rocks needed for the border is $1560!

8 0
4 years ago
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