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Advocard [28]
3 years ago
11

Solve the following. 2x^2-7x-4/6x^2+7x+2<0 Can someone explain how to solve this.

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
4 0

Answer:

Which one have same variable gather or decrease up

Step-by-step explanation:

2x^2-4.6x^2=1.4x^2

-7x+7x=0

1.4x^2+2<0

x<0

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Lunna [17]

Answer:

The Product of 7⋅(−4)⋅(−6) −168 −3 is<em> </em><u>-3</u>

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Carl and rose live in the same straight road. From their balconies they can see a flagpole in the distance. The angle that each
Andreyy89

Carl and Rose' balconies make up the base of an isosceles triangle.

Their distances from the flagpole is the same.

From the question, we understand that:

  • Carl and Rose live on a straight line
  • The measure of angle from each person's balcony to the flagpole is the same

The above highlights mean that:

The relationship between Carl and Rose' balconies and the flagpole is an isosceles triangle.

Where Carl and Rose' balconies form the base of the isosceles triangle.

Hence, their distances from the flagpole is the same.

Read more about distances at:

brainly.com/question/12961022

6 0
3 years ago
5x-2y 2.4what is the constant
Vikki [24]
 i think the constant is 1.2
7 0
3 years ago
Find f(-2) for f(x)=3×2x​
Ronch [10]

substitute every x in the equation with (-2)

f(-2)=3*2*(-2) = -12

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7 0
3 years ago
Please help <br><br>1 through 3​
Wewaii [24]

Answer:

  1. object is moving to the right with constant speed
  2. object is moving to the left with constant speed
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Step-by-step explanation:

These graphs are of position, so the slope of the graph is the change of position with time, which is velocity. When the slope is positive, the velocity is positive, meaning its direction is to the right. When the slope is negative, the velocity is negative, meaning its direction is to the left.

When the slope is zero, the object is stationary (not moving). The position remains as it was.

1. The position vs. time curve is a straight line with positive slope. The object is moving to the right with constant velocity.

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2. The position vs. time curve is a straight line with negative slope. The object is moving to the left with constant velocity.

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3. The position vs. time curve is flat for a while, then increasing with constant slope. The object stayed where it was for a while, then began moving to the right (to larger values of x) with constant velocity.

7 0
4 years ago
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