Substituting this into the other ODE gives
Since 
, it follows that 
. The ODE in 
has characteristic equation
with roots 
, admitting the characteristic solution
From the initial conditions we get
So we have
Take the derivative and multiply it by -1/4 to get the solution for 
:
Answer:
Step-by-step explanation:
6(x²+15)
5/10 in the lowest fraction is 1/5
The decimal form is 0.5 if you need it
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*=y so, the * is y at the end of the word
Answer:
The equation of the required line is y = x + 5
Step-by-step explanation:
The equation of the given line is y = x - 2
The required line = A line parallel to the given line
The point through which the required line passes = (-3, 2)
The general form of the equation of a straight line, is y = m·x + c
Where;
m = The slope of the line
By comparison, the slope of the given line, m = 1
When two lines are parallel, their slope are equal
Therefore, the slope of the required line = m = 1
The equation of the required line in point and slope form is therefore;
y - 2 = x - (-3) = x + 3
∴y = x + 3 + 2 = x + 5
The equation of the required line is therefore;
y = x + 5.
Answer:
Height of building from base to ladder = 5.8 meter (Approx.)
Step-by-step explanation:
Given:
Length of ladder = 6 meters
Distance of ladder from base = 1.5 meters
Find:
Height of building from base to ladder
Computation:
Perpendicular = √Hypotenuse² - Base²
Height of building from base to ladder = √Length of ladder² - Distance of ladder from base²
Height of building from base to ladder = √6² - 1.5²
Height of building from base to ladder = √36 - 2.25
Height of building from base to ladder = √33.75
Height of building from base to ladder = 5.8 meter (Approx.)
