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Firlakuza [10]
3 years ago
9

Evan ran 9 and 3/5 miles in one hour and twenty four minutes. Find the average of minutes it took him to complete one mile.

Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0

Answer:bdbdhdb

Step-by-step explanation:

Bfhdhdbbs

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ahrayia [7]
2x + 8 would be the simplified version of this question
8 0
2 years ago
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. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar
yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are  K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

\frac{270}{455}=0.5934=59.34\%

(b)

The probability of selecting three 40-W bulbs is

\frac{4*3*2}{455}=0.0527=5.27\%

The probability of selecting three 60-W bulbs is

\frac{5*4*3}{455}=0.1318=13.18\%

The probability of selecting three 75-W bulbs is

\frac{6*5*4}{455}=0.2637=26.37\%

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

\frac{6*5*4}{455}=0.2637=26.37\%

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is \frac{9}{15}=0.6

Since there are no replacement, the probability of taking a second non 75-W bulb is now \frac{8}{14}=0.5714

Following this procedure 5 times, we find the probabilities

\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0
3 years ago
Plz asap maxium points will mark brainliest
Mariana [72]

Answer:

12

Step-by-step explanation:

We know that AD=BC and that AB=CD. We also know the perimeter of the rectangle ABCD to be 54 units.

From this, we can add up the sides which will be equal to 54 units.

AD+BC+AB+CD=54

2x+2x+3x-3+3x-3=54

10x=60

x=6

Since we are trying to find the length of side BC we substitute this value back into 2x.

BC=2x =2*6=12

Therefore, the length of BC is 12 units.

4 0
3 years ago
write an equation in slope-intercept form of the line that passes through the points (1,2) and (-2,-1)
Marizza181 [45]

Answer:

y=3/4x+5/4

Step-by-step explanation:

equation to use: y1-y2/x2-x1 so you get -3/-4 so your slope is 3/4 and you plug that into one of your point equations im going to use the first one so 2=3/4(1) +b so you are going to get 5/4 for b so your equation is y=3/4x + 5/4

Let me know if this helped!

6 0
3 years ago
Read 2 more answers
Need help with this if anyone can
sattari [20]

9514 1404 393

Answer:

  7.0

Step-by-step explanation:

The relationship of interest is ...

  Tan = Opposite/Adjacent

  tan(25°) = x/15

  x = 15·tan(25°) ≈ 6.9946

  x ≈ 7.0

5 0
3 years ago
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