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3 years ago

Which equation could represent the relationship shown in the scatter plot?

Mathematics

2 answers:

BigorU [14]3 years ago

6 0

Answer:

y = 7/8x + 6

-Hope This Helps

Dafna1 [17]3 years ago

6 0

Answer:

it is y=78 x +6 thats correct

Step-by-step explanation:

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Dada la siguiente serie numérica: ..., –7, -4, -1, 2, 5, ... ¿Cuál es la suma del número entero

Ymorist [56]

Answer:

-5

Step-by-step explanation:

el número anterior a -7 es -10 y -10+5 es -5

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3 years ago

Find (x+3) (x^2 - 2x -8). Write answer in standard form

Pavlova-9 [17]

Answer:

x3+x2-14x-24

Step-by-step explanation:

8 0

3 years ago

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Amir stands on a balcony and throws a ball to his dog, who is at ground level. The ball's height (in meters above the ground), x

kumpel [21]

Answer:

12m

Step-by-step explanation

If the height of the ball after x seconds be modelled by the equation

h(x)=−(x−2)² +16

The height of the ball at the time it is thrown will be the height at the initial time. At that point that it is initially thrown the time is 0seconds i.e x = 0

To get the height at t x = 0seconds, we will substitute x = 0 into the modeled function to have;

h(0) = -(-0-2)²+16.

h(0) = -(-2)²+16

h(0) = -4+16

h(0) = 12

The height of the ball at the time the ball is thrown is 12m

4 0

4 years ago

Read 2 more answers

Whats the volume of the prism please show work‼️

attashe74 [19]

Answer:

Step-by-step explanation:

Volume of a prism:

Area of cross section x height

4 0

3 years ago

An article in Knee Surgery, Sports Traumatology, Arthroscopy, "Arthroscopic meniscal repair with an absorbable screw: results an

igomit [66]

Answer:

Mean = 1.57

Variance=0.31

Step-by-step explanation:

To calculate the mean and the variance of the number of successful surgeries (X), we first have to enumerate the possible outcomes:

1) Both surgeries are successful (X=2).

$P(e_1)=0.90*0.67=0.603$

2) Left knee unsuccessful and right knee successful (X=1).

$P(e_2)=(1-0.9)*0.67=0.1*0.67=0.067$

3) Right knee unsuccessful and left knee successful (X=1).

$P(e_3)=0.90*(1-0.67)=0.9*0.33=0.297$

4) Both surgeries are unsuccessful (X=0).

$P(e_4)=(1-0.90)*(1-0.67)=0.1*0.33=0.033$

Then, the mean can be calculated as the expected value:

$M=\sum p_iX_i=0.603*2+0.067*1+0.297*1+0.033*0\\\\M=1.206+0.067+0.297+0\\\\M=1.57$

The variance can be calculated as:

$V=\sum p_i(X_i-\bar{X})^2\\\\V=0.603(2-1.57)^2+(0.067+0.297)*(1-1.57)^2+0.033*(0-1.57)^2\\\\V=0.603*0.1849+0.364*0.3249+0.033*2.4649\\\\V=0.1115+0.1183+0.0813\\\\V=0.3111$

3 0

3 years ago