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Paha777 [63]
2 years ago
14

In the game of Twister, a spinner randomly selects either an arm or a leg, and also selects one of four colors, one of which is

red, each with equal probability, and players have to move the appropriate body part to the appropriately colored spot on the ground. There are four players. Each player spins once, and makes the move the spinner selects. What is the probability that in these four spins, there will be exactly two moves to a red spot, and the body part selected to move will be an arm exactly $3$ times
Mathematics
1 answer:
Aleksandr [31]2 years ago
8 0

Answer:

In agreement to your twister question, a spinner can randomly select whether they want to put an arm or a leg, meaning this choice is entirely upon them. The color choice is also independent, so spinners are allowed to choose freely, whichever color as well as limb they want to move in the game of twister.

See the attached image for step by step explanation of the final probability

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Four students about to purchase concert tickets for $20.00 for each ticket discover that they may purchase a block of 5 tickets
CaHeK987 [17]

Answer:

Each student's contribution = $17

Each student will save $ 3

Step-by-step explanation:

Cost of the block of 5 tickets is $85.00.

Dividing the $ 85 by 5 would give the equal amount each would have to contribute.

$ 85/5=$ 17

Each will have to pay $ 17 to buy a block of 5 tickets for $85.00.

We can find the amount each will save by subtracting the amount to be shared by the 5 students from the amount paid by the 4 students.

They will save

$ 20-$17=

$3

Each of them will save $3 if they can get a fifth person to join them and the 5 people equally divide the price of the 5-ticket block.

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3 years ago
Simplify the expression; 2^3 x 2^2<br> A. 2^5<br> B. 4^6 <br> C. 4^5<br> D. 2^6
Illusion [34]

Answer:

Simplify the expression; 2^3 x 2^2

<u>A. 2^5 </u>

B. 4^6  

C. 4^5

D. 2^6

Step-by-step explanation:

You add the powers together since you are multiplying.

8 0
3 years ago
Read 2 more answers
Can someone plz help me with this!
asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

2x+y=10\\x-3y=-2

To solve, start by isolating your first equation for y.

2x+y=10\\y=-2x+10

Now, plug this value of y into your second equation.

x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4

System #2: x=1

x+2y=5\\2x+y=4

Isolate your second equation for y.

2x+y=4\\y=-2x+4

Plug this value of y into your first equation.

x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1

System #3: x=6

5x+y=33\\x=18-4y

Isolate your first equation for y.

5x+y=33\\y=-5x+33

Plug this value of y into your second equation.

x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6

System #4: all real numbers (not included in your diagram)

y=13-2x\\8x+4y=52

Plug your value of y into your second equation.

8x+4(13-2x)=52\\8x+52-8x=52\\0=0

<em>all real numbers are solutions</em>

System #5: x=2

x+3y=5\\6x-y=11

Isolate your second equation for y.

6x-y=11\\-y=-6x+11\\y=6x-11

Plug in your value of y to your first equation.

x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2

System #6: no solution (not included in your diagram)

2x+y=10\\-6x-3y=-2

Isolate your first equation for y.

2x+y=10\\y=-2x+10

Plug your value of y into your second equation.

-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2

<em>no solution</em>

System #7: x=3

y=10+x\\2x+3y=45

Plug your value of y into your second equation.

2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3

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The answer is c 438 in 2
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mario62 [17]

Answer:

27

Step-by-step explanation:

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