V = a * b * c
V = 30
a = 5
b = 2
c = ?
30 = 5*2*c
30 = 10*c
c = 30/10 = 3
c = 3
Answer:
4/675
Step-by-step explanation:
There can be 90 two-digit numbers ranging from 10 to 99. There will be
90 x 90= 8100 possibilities of randomly selecting and combining 2 entire two-digit numbers, if we find ax b to be distinct from bx a. When 10 is first chosen, there may be 9 two-digit numbers that could be combined within the required range for a product When 11 is chosen first, then the second two-digit number has 9 possibilities. 12 has seven options; 13 has six options; 14 has five options; 15 has four options; 16 has three options; 17 has two options; 18 has 2 options; and 19 has one option. It provides us 48 total choices so the likelihood that the combination of two randomly chosen two-digit whole numbers is one of theses these possibilities is thus 48/8100 = 4/675.
Answer:
ok so the answer is b
Step-by-step explanation: because if you divide the numbers and you get the answer you will have to add and there is your answer and please give me a 5 star.
Answer:
The sum of first five term of GP is 19607.
Step-by-step explanation:
We are given the following in the question:
A geometric progression with 7 as the first term and 7 as the common ration.
Sum of n terms in a geometric progression:
For sum of five terms, we put n= 5, a = 7, r = 7
The sum of first five term of GP is 19607.
Verification:
Thus, the sum is equal to product of 2801 and 7.
1 1/9
To figure out how much walnuts to a pound of dried fruit you’d need to do proportions. So we cross multiply:
2/3 = X
—————- —————-
3/5 = 1
You multiply diagnols 2/3 x 1 = 2/3
3/5 times x is 3/5x.
2/3 = 3/5x. Isolate the variable. Divide 3/5 on both sides cancel out 3/5. 2/3 divide by 3/5 is 2/3 x 5/3 which is 10/9 which equals 1 1/9.
So for 1 lb of dried fruit you need 1 1/9 lb of walnuts to maintain the same mixture
