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galina1969 [7]
2 years ago
13

Consider the following two quantities:

Mathematics
1 answer:
inessss [21]2 years ago
6 0

The slope of the line is -2.5 and the y-intercept is 2. This shows that the Quantity B is greater that A

<h3>How to find the intercept of a line</h3>

The intercept is the point where the line intersects

Determine the slope of the graph using the coordinate points (0, 2) and (0.8, 0)
Slope = -2/0.8
Slope = -2.5

The slope of the line is -2.5 and the y-intercept is 2

This shows that the Quantity B is greater than A

Learn more on equation of a line here:brainly.com/question/13763238

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Simplify the expression.<br> (4a- 80 - 4a2) + (7a3 - 7 - 6a)
allsm [11]

Answer:

the answer should be 7a^3-4a^2-2a-87

3 0
3 years ago
I am offering another 100 points
Ivahew [28]

Answer:

\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.

Step-by-step explanation:

<u>Perfect squares</u>: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find \sf \sqrt{75} , identify the perfect squares immediately <u>before</u> and <u>after</u> 75:

  • 64 and 81

\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}

\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.

See the attachment for the correct placement of \sf \sqrt{75} on the number line.

6 0
1 year ago
Read 2 more answers
Who can help me with this plzz
Brrunno [24]
.04d + 20. 

This is because even with no miles they charge 20 more and then 4 cents more for any additional mile. 
6 0
3 years ago
The product of 162 and m is the same as 17
elena-s [515]

Answer:

No

Step-by-step explanation:

Just took a test

5 0
3 years ago
Please answer 26 and 27 please thank you
ser-zykov [4K]

Answer:

Part 26) 3\frac{1}{4}\ in

Part 27) 2\frac{2}{3}\ cups

Step-by-step explanation:

Part 26)

we know that

The length of Alana's hair was 9 3/4 inches

After her haircut, the length was 6 1/2 inches

To find out how many inches did she have cut subtract 6 1/2 from 9 3/4

but first

Convert mixed number to an improper fraction

9\frac{3}{4}\ in=\frac{9*4+3}{4}=\frac{39}{4}\ in

6\frac{1}{2}\ in=\frac{6*2+1}{2}=\frac{13}{2}\ in

Find the difference

\frac{39}{4}-\frac{13}{2}=\frac{39-26}{4}=\frac{13}{4}\ in

Convert to mixed number

\frac{13}{4}\ in=\frac{12}{4}+\frac{1}{4}=3\frac{1}{4}\ in

Part 27)

we have that

Emeril used a total of 7 1/4 cups of flour to make three pastries

He used 2 1/4 cup of flour for the first and 2 1/3 cups of flour for the second

To find out how much cups of flour Emeril use for the third pastry, subtract the sum of the cups of flour used in the first and second pastry from the total cups of pastry used

Let

x ----> number of cups of flour used in the third pastry

x=7\frac{1}{4}-(2\frac{1}{4} +2\frac{1}{3})

but first

Convert mixed number to an improper fraction

7\frac{1}{4}\ in=\frac{7*4+1}{4}=\frac{29}{4}\ cups

2\frac{1}{4}\ in=\frac{2*4+1}{4}=\frac{9}{4}\ cups

2\frac{1}{3}\ in=\frac{2*3+1}{3}=\frac{7}{3}\ cups

substitute

x=\frac{29}{4}-(\frac{9}{4} +\frac{7}{3})

x=\frac{20}{4} -\frac{7}{3}

x=\frac{20*3-7*4}{12}

x=\frac{32}{12}\ cups

Simplify

x=\frac{8}{3}\ cups

Convert to mixed number

\frac{8}{3}=\frac{6}{3}+\frac{2}{3}=2\frac{2}{3}\ cups

4 0
2 years ago
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